The derivative with respect to 'x' is 4y3 . The derivative with respect to 'y' is 12xy2 .
The derivative, with respect to x, is -x/sqrt(1-x2)
well if you're finding the derivative with respect to x, it would be -tx^(-t-1)
d/dx ∫ f(x) dx = f(x)
- the derivative with respect to x is 40y - The derivative with respect to Y is 40xSo, since both x and y equal 2, both derivatives yield 40*2 = 80
The derivative with respect to 'x' is 4y3 . The derivative with respect to 'y' is 12xy2 .
The derivative with respect to 'x' of sin(pi x) ispi cos(pi x)
If it is with respect to t: 1 If it is with respect to some other variable (x for example): (dt)/(dx), which is literally read "the derivative of t with respect to x"
The derivative, with respect to x, is -x/sqrt(1-x2)
well if you're finding the derivative with respect to x, it would be -tx^(-t-1)
d/dx ∫ f(x) dx = f(x)
- the derivative with respect to x is 40y - The derivative with respect to Y is 40xSo, since both x and y equal 2, both derivatives yield 40*2 = 80
If y = 3x +- 1, the derivative with respect to x is y' = 3.
Yes, the derivative of xi with respect to x equals i. Is that what you were trying to ask?
If the differentiation is carried out with respect to 'x', then it's 3x2 .
A partial derivative is the derivative of a function of more than one variable with respect to only one variable. When taking a partial derivative, the other variables are treated as constants. For example, the partial derivative of the function f(x,y)=2x2 + 3xy + y2 with respect to x is:?f/?x = 4x + 3yhere we can see that y terms have been treated as constants when differentiating.The partial derivative of f(x,y) with respect to y is:?f/?y = 3x + 2yand here, x terms have been treated as constants.
Well, isn't that just a happy little question! When you take the derivative of 2Y with respect to Y, you simply get 2. It's like painting a beautiful landscape - just follow the rules and let the magic happen!