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1/(1-x)2dx

We can rewrite the integral as (1-x)-2dx.

Thus:

(1-x)-2dx

u = 1-x

du = -1

-1-1(1-x)-2dx

-1u-2du

(u-1|0u=1-x

(1-x)-1

So we conclude that 1/(1-x)2dx = (1-x)-1 or 1/(1-x)

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Q: What is the integral of 1 over 1 minus x squared?
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