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∫1/(1-x)2dx

We can rewrite the integral as ∫(1-x)-2dx.

Thus:

∫(1-x)-2dx

u = 1-x

du = -1

-1∫-1(1-x)-2dx

-1∫u-2du

(u-1|0u=1-x

(1-x)-1

So we conclude that ∫1/(1-x)2dx = (1-x)-1 or 1/(1-x)

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∙ 17y ago

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