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2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
2x - y -(-1) = 2x - y + 1
y = 2x + 15 y = 4x + 7 Substitute the value of y from the first equation into the second: 2x + 15 = 4x + 7 Subtract 2x from both sides: 15 = 2x + 7 Subtract 7 from both sides: 8 = 2x Divide both sides by 2: 4 = x. Replace x by its value, 4, in the first equation: y = 2*4 + 15 = 8 + 15 = 23 So the solution is (x, y) = (4, 23)
Substitute 2x - 6 for y in first equation: 12x - 5(2x - 6) = 30 ie 12x - 10x + 30 = 30 so 2x = 0 making x = 0 and y = -6