4
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
2x - y -(-1) = 2x - y + 1
y = 2x + 15 y = 4x + 7 Substitute the value of y from the first equation into the second: 2x + 15 = 4x + 7 Subtract 2x from both sides: 15 = 2x + 7 Subtract 7 from both sides: 8 = 2x Divide both sides by 2: 4 = x. Replace x by its value, 4, in the first equation: y = 2*4 + 15 = 8 + 15 = 23 So the solution is (x, y) = (4, 23)
Substitute 2x - 6 for y in first equation: 12x - 5(2x - 6) = 30 ie 12x - 10x + 30 = 30 so 2x = 0 making x = 0 and y = -6
-2x = y^5 or y^5 = -2x y = (-2x)^(1/5)
7
What is the answer to Y=19-2x. X=3
y5 * y3 * y = y5 * y3 * y1 = y5+3+1 = y9
Factors of x5 . . . 1, x, x2, x3, x4, and x5, as well as any factors of 'x', and their powers. Factors of y5 . . . 1, y, y2, y3, y4, and y5, as well as any factors of 'y', and their powers.
The derivative of x3-2x+5 is 3x2- 2. This is its slope at a point x,y.
5x + 5y = 5(x+y)
(27 times 18)y5 / (9 times 6)y = 486y5 / 54y = 9y4
3x - y = 3y = 2x + 2Put the value of y in the 1st equation:3x - y = 3 it will be -->3x - ( 2x + 2 ) = 33x - 2x - 2 = 3x - 2 = 3X = 5Put the value of X in the 2nd equation so as to find the value of Y :y = 2x + 2y = 2(5) + 2y = 10 + 2Y = 12
(x + y)3 + (x - y)3 = (x3 + 3x2y + 3xy2 + y3) + (x3 - 3x2y + 3xy2 - y3) = 2x3 + 6xy2 = 2x*(x2 + 3y2)
It is 1/y5
3