so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x, therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2 therefore, (Ln + [X/3]) = 1
It is impossible but if it were x squared plus 2x minus 15 the equation would be (x+5) (x-3) with x being equal to either -5 or 3. If the original problem was x squared minus 2x minus 15 the equation would be (x-5)(x+3) and x would be equal to either 5 or -3
x over x is one, so the problem would be 1-2-3/2=-5/3
-2, 3
Dividend: x3+4x2-9x-36 Divisor: x+3 Quotient: x2+x-12
x + 1
-3
x³ + x² - 3x - 3 = (x + 1)(x + √3) (x - √3).
If: 24 = 6-x-3 Then: x = -21
so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x, therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2 therefore, (Ln + [X/3]) = 1
x5
x(x + 3)(x - 4)
(x - 5)(x + 3)
By factoring I get x-3 divided by x+3
x³ - x² + x - 3 (x² + 1)(x - 1) - 2
3-2 x 3-3 = 3-5 or 1/243
x - 3