3-2 x 3-3 = 3-5 or 1/243
-3
-6
x2_12x-3 = 0 Using the formula for solving quadratics: x = 12 plus/minus sqrt (144 - (4 x 1 x -3))/2 x = 12 plus/minus (sqrt 156)/2 x = 12 + (sqrt 156)/2 = 12.25 or x = 12 - (sqrt 156)/2 = -0.25
3x2 when x = 2 is the answer 3 X 4 = 12 or is the answer (3 X 2)2 = 62 = 36
x = +11 or -11
x5
x4 - x2 - 12 = (x2 + 3) (x2 - 4)And (x2 - 4) = (x + 2) (x - 2)So the original expression = (x2+ 3) (x + 2) (x - 2)
(-3)2 = -3 x -3 = 9 - 32 = - 3 x 3 = -9
3(x - y)(x + y)
Yes, it is.
3x^2 - 27 = = 3(x^2 - 9) = 3(x^2 - 3^2) = 3(x - 3)(x + 3)
(2x - 3)(3x + 2)
3x^4 - 12 = 3(x^4 - 4) = 3(x² + 2)(x² - 2)
(2/3)X = (3/2)-1 (2/3)X = (2/3) So X = 1
so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x, therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2 therefore, (Ln + [X/3]) = 1
-3
1 and the positive and negative square roots of 2