pH is a logarithmic scale; because of the way calculus and maths works, graphing such a scale against a log results in a straight line.
The graph of y = log(x) is defined only for x>0. The graph is a monotonic increasing function over its domain. It starts from an asymptotic "minus infinity" when x approaches 0. It passes through the value y = 0 when x = 1. The graph is illustrated at the link below.
An exponential function can be is of the form f(x) = a*(b^x). Some examples are f1(x) = 3*(10^x), or f2(x) = e^(-2*x). Note that the latter still fits the format, with b = e^(-2). The inverse is the logarithmic function. So for y = f1(x) = 3*(10^x), reverse the x & y, and solve for y:x = 3*(10^y)log(x) = log(3*(10^y)) = log(3) + log(10^y) = log(3) + y*log(10) = y*1 + log(3)y = log(x) - log(3) = log(x/3)The second function: y = e^(-2*x), the inverse is: x = e^(-2*y).ln(x) = ln(e^(-2*y)) = -2*y*ln(e) = -2*y*1y = -ln(x)/2 = ln(x^(-1/2))See related link for an example graph.
For a quotient x/y , then its log is logx - log y . NOT log(x/y)
A log-log scale is a set of axes where each axis is logarithmic in scale.
to log in friendster.com
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linear: LINE example--- line non-linear: not a LINE example--- parabola The other possibility is a graph with a non-linear scale. First a linear scale will have each unit represent the same amount, regardless of where you are on the scale. A semilog scale, has a linear scale in the horizontal direction, and a logarithmic scale in the vertical direction. Exponential functions (such as ex & 10x), will graph as a straight line on this type of graph scale). A logarithmic or log-log scale, has logarithmic scales on both horizontal and vertical axis. Power functions (such as sqrt(x), x2 and x3), graph as a straight line on these scales. See Related Link
The graph of ( \log(x) + 6 ) is a vertical translation of the graph of ( \log(x) ) upwards by 6 units. This means that every point on the graph of ( \log(x) ) is shifted straight up by 6 units, while the shape and orientation of the graph remain unchanged. The domain of the function remains the same, which is ( x > 0 ).
Not necessarily. It depends on the graph "paper" used. For example, you can get semi-log graph paper in which the x-axis is normal but the y-axis has a logarithmic scale. This feature is available on Excel in "format axis". On such a coordinate system, an exponential equation becomes a straight line.
If y=xn, then log y =nlogx and n indicates the power in the power function. If one has a set of data [x,y] and if a plot of logy vs logx yields a straight line or one reasonably so, then the slope (gradient) of the line reveals the power relation between x and y
To prove graphically that a reaction is first order, you would plot the natural log of the concentration of the reactant versus time. If the resulting graph is linear, then the reaction is first order. This linear relationship indicates that the rate of the reaction is directly proportional to the concentration of the reactant.
Yes, the resulting function is a straight line. This is the source:http://www.mathbench.umd.edu/mod207_scaling/page10.htm
A normal graph plot one variable against another. If one of these variable has a very rapid rate of growth it would quickly disappear off the graph. If you used a graph large enough to show the entire range you would lose much of the detail at the lower end. Using a log or semi-log graph reduces the rate of change whilst still allowing you to represent the relationship between the variables. You can see an example of log graph paper using the lnk in the related links section below.
A graph that shows the plotted course of a logarithmic expression.
The graph of log base b(x-h)+k has the following characteristics. the line x = h is a vertical asymptote; the domain is x>h, and the range is all real numbers; if b>1, the graph moves up to the right. of 0>b>1, the the graph moves down to the right.
in our syllabus there is only the first and the zero order reaction in which if the graph is plotted between the concentration and time then it is a zero order reaction while if the graph is between the log of concentration and time then the reaction is of the first order.hope this will help u.
why would you use a semi-logarithmic graph instead of a linear one?what would the curve of the graph actually show?