3x+y=-1 y=-1-3x5x-y=9 5x-(-1-3x)=95x+1+3x=98x=8x=1y=-1-3(1)y=-4(1,-4)
3x + y = c where c is any constant number of your choice.
Get in function form. - 3X - Y = 4 - 1(- Y = 3X + 4) Y = - 3X - 4 ----------------------------solve for X and Y by the 0 out method - 3X - 4 = 0 - 3X = 4 X = - 4/3 --------------- Y = - 3(0) - 4 Y = - 4 -------------- Draw a line linking those points.
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3x - 9y = 27-9y = -3x + 279y = 3x - 27y = x/3 - 3The graph is a straight line, with (slope = 3), and passing through the point (y = - 3) on the y-axis.
3x + y = -1 y = -3x - 1 The graph is a straight line, with a slope of -3, passing through the point Y = -1 on the y-axis.
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1
(a) y = -3x + 1
y=7x+1 ( apex )
If you graph this it will be a parabola that has each end pointing down. It crosses the x-axis at: y=-2x^2+3x+5 y=-1(2x^2-3x-5) y=-1(2x-5)(x+1) y=5/2 y=-1
y = 3x + 1 is a linear equation - it is the equation for a graph of a straight line that crosses the y axis at 1 and the x axis at -1/3, and has a gradient (slope) of 3.
y=7-3x
y = 3X - 1
y = 3x + 1
y-3x-3 y=3x+3 A line with a slope of 3 crossing the y-axis at 3.
3x + y = 7 First, turn the equation into the slope-intercept form, y = mx + b, where m is the slope of the graph that that equation represents (solve for y).3x + y = 7 subtract 3x to both sidesy = -3x + 7So you clearly see that the slope is -3.