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Y=3x+1 A straight line crossing the y-axis at (0,1) and having a relatively steep slope of 3 up and 1 over.
answer is 1
Get in function form. - 3X - Y = 4 - 1(- Y = 3X + 4) Y = - 3X - 4 ----------------------------solve for X and Y by the 0 out method - 3X - 4 = 0 - 3X = 4 X = - 4/3 --------------- Y = - 3(0) - 4 Y = - 4 -------------- Draw a line linking those points.
Let's try natural logs. 4e^(3X+1) = 10 divide both sides by 4 e^(3X+1) = 5/2 ln[e^(3X+1)] = ln(5/2) 3X+1 lne = ln(5/2) 3X+1 = ln(5/2)/lne ( natural log of e = 1, of course ) 3X + 1 = 5/2 subtract 1 from each side 3X = 3/2 divide each side by 3 X = 1/2