The number of distinct combinations that can be created with n bits is 2n.
32 Bits 4 Octets with 1 Byte each(8 Bits)
5 bits
A 264-bit system has 64 bits.
4 bytes are equivalent to 32 bits.
How many bits are there in a data link layer ethernet address?
4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.
26 = 64
Each bit allows 21 combinations. Accordingly, n number of bits provide 2n combinations.Therefore, 5 bits provide 25 = 32 combinations. # 00001 # 00010 # 00011 # 00100 # 00101 # 00110 # 00111 # ...
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb
8192
32 values. 2^5=32
For every bit, there are two combinations. For 12 bits, you need to multiply all together: 2 x 2 x 2 x ... x 2, or 2 to the power 12, which is equal to 4096.
There are infinite combinations that can make 3879
9!/6!, if the six different orders of any 3 digits are considered distinct combinations.
There are 126 different 5 digit combinations. Note that the combination 12345 is the same as the combination 45312.
1 byte is 8 bits. That's 8 1s or 0s. 2 bytes is 8*2=16 bits (1s/0s). That is 2^16=65536 possibilities. Therefore, there are 65,536 different combinations with 2 bytes.
A byte is 8 bits. Thus, 32 bytes is 256 bits. Bits are each either a single 1 or 0. By statistics, you then have 2256 possible combinations. In other words, 32 bytes can represent any number from 1 to 1.15792089 × 1077.