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The number of distinct combinations that can be created with n bits is 2n.

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5mo ago

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How many combinations of bits are possible with two bits?

With two bits, there are (2^2) possible combinations, which equals 4. The combinations are: 00, 01, 10, and 11. Each bit can be either 0 or 1, leading to these four distinct configurations.


How many bits are needed in order to represent the decimal values from 0 to 15?

4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.


How many combinations can be formed from 6 bits?

26 = 64


How many combinations can be formed from 5 bits?

Each bit allows 21 combinations. Accordingly, n number of bits provide 2n combinations.Therefore, 5 bits provide 25 = 32 combinations. # 00001 # 00010 # 00011 # 00100 # 00101 # 00110 # 00111 # ...


How many different combinations are represented by 10 bits?

A 10-bit binary number can represent (2^{10}) different combinations. This is because each bit can be either 0 or 1, leading to (2) choices for each of the (10) bits. Therefore, (2^{10} = 1024) different combinations can be represented by 10 bits.


How many combinations can be formed by 5 bits in binary system?

In a binary system, each bit can be either 0 or 1. Therefore, for 5 bits, the total number of combinations can be calculated as (2^5). This results in 32 different combinations, ranging from 00000 to 11111.


How many 4 number combinations using 5 numbers?

There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb


A memory location 13 bits wide represents how many distinct values?

8192


How many combinations can be formed from 12 bits?

For every bit, there are two combinations. For 12 bits, you need to multiply all together: 2 x 2 x 2 x ... x 2, or 2 to the power 12, which is equal to 4096.


How many distinct values can we represent with 5 bits?

32 values. 2^5=32


How many combinations in 3879?

There are infinite combinations that can make 3879


How many 3 digit combinations numbers one through nine?

9!/6!, if the six different orders of any 3 digits are considered distinct combinations.