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it depends, please give an example of the equation.

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Q: How do you solve an equation with 5 terms?
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How do you solve this equation (x plus 3) -5 squared?

With great difficulty because without an equality sign the given terms can't be considered to be an equation.


Can you solve the equation 6 equals -10-p over 5?

If the equation is 6 = -10 - p/5 then multiply all terms by 5 :-30 = -50 - p : p = -50 - 30 = -80


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The question contains an algebraic expression but there is no equation to solve.


How do you solve the equation 7r2 equals 70r-175?

7r2 = 70r-175 Rearrange the equation and treat it as a quadratic equation: 7r2-70r+175 = 0 Divide all terms by 7: r2-10+25 = 0 Solve by factoring or using the quadratic equation formula or by completing the square: (r-5)(r-5) x = 5 and x also = 5 (they both have equal roots)


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How do you the solve the equation x equals 2y in terms of x?

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What is x2plus6xplus 5?

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How do you solve the equation -3x minus 5 equals -20?

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How does simplifying an expression help you to solve an equation efficiently?

It combines like terms and results in the least amount if variables to solve for


How do you solve 10a plus 5b?

You can't just solve one side of the equation. You always have to have both sides of the equal sign in order to manipulate the terms. If you have an equation like 10a + 5b=0, you can now solve for one of the terms (a or b), for example, b=10a/5 and a=-5b/10. Once you have solved for one term, you can plug it back into the equation and solve for real values. In this particular equation, a=-1/2b so by putting any value in for b (say 2), you get a definite value for a (-1) but there are an infinite number of such values.