A 500 MCM copper conductor will limit the voltage drop to 3% or less when supplying 50 amps for 800 feet on a 120 volt system. 500 MCM wire diameter is 1/2 inch. As you can see there will be trouble getting that size wire into a 50 amp breakers lug. On installations like this to offset the voltage drop at such a low voltage, a transformer should be used at both ends. The first transformer to raise the voltage and the second transformer to lower it at the 800 foot end. If you use two 480 volt transformers a #1 wire can be used between them. A #1 copper conductor will limit the voltage drop to 3% or less when supplying 50 amps for 800 feet on a 480 volt system. By increasing the voltage you can see that a smaller wire size can be used. On an installation of this nature, a primary line should be brought to the RV site and a service distribution panel established at that point and any RV vehicles can then be fed from that service.
To answer this question you have to know the voltage and load type. If this was a 110 Volt lighting application 12-2 should work. If this was a 220 Volt motor load 10-2 might be a better choice. Copper wire 120 volts #6, at 240 volts #8. Aluminium wire 120 volts #4, at 240 volts #6. As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed. Before you do any work yourself,on electrical circuits, equipment or appliances,always use a test meter to ensure the circuit is, in fact, de-energized.IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOBSAFELY AND COMPETENTLYREFER THIS WORK TO QUALIFIED PROFESSIONALS.
Amps * Volts = Watts Amps * 12 = 600 600/12 = Amps = 50 amps You would need a reserve capacity, so I'd go somewhere between 60 or 100 Amp rated transformer. Transformers are rated in volt-amps which is usually calculated the same as watts. But the term "watts" technically does not apply to transformers. So you need a 600 volt-amp transformer or, as Redbeard has suggested, you need an 800 or 1000 volt-amp transformer. That's a lot of amps for a 12 volt system so I recommend you double check your requirements. You will need a #2 gauge wire if your requirements are correct.
600amps
This is a voltage drop question. To answer this question a voltage has to be stated. The higher the voltage to the circuit becomes the smaller the wire size needed. After a certain voltage point the wire size will remain constant and the voltage drop at the load will become smaller.
No, to show you I would have to be there with you and I am not.
This is a voltage drop question and a voltage needs to be stated.
A 500 MCM copper conductor will limit the voltage drop to 3% or less when supplying 50 amps for 800 feet on a 120 volt system. 500 MCM wire diameter is 1/2 inch. As you can see there will be trouble getting that size wire into a 50 amp breakers lug. On installations like this to offset the voltage drop at such a low voltage, a transformer should be used at both ends. The first transformer to raise the voltage and the second transformer to lower it at the 800 foot end. If you use two 480 volt transformers a #1 wire can be used between them. A #1 copper conductor will limit the voltage drop to 3% or less when supplying 50 amps for 800 feet on a 480 volt system. By increasing the voltage you can see that a smaller wire size can be used. On an installation of this nature, a primary line should be brought to the RV site and a service distribution panel established at that point and any RV vehicles can then be fed from that service.
120/800 which reduces to 3/20
To answer this question you have to know the voltage and load type. If this was a 110 Volt lighting application 12-2 should work. If this was a 220 Volt motor load 10-2 might be a better choice. Copper wire 120 volts #6, at 240 volts #8. Aluminium wire 120 volts #4, at 240 volts #6. As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed. Before you do any work yourself,on electrical circuits, equipment or appliances,always use a test meter to ensure the circuit is, in fact, de-energized.IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOBSAFELY AND COMPETENTLYREFER THIS WORK TO QUALIFIED PROFESSIONALS.
first you find 15% of 800. 800/100 is 8, x15 = 120. 800-120 is 680
For an 800 amp service, typically a 3/0 or 4/0 copper conductor or 250kcmil aluminum conductor would be appropriate for the grounding wire. However, it is recommended to consult with a qualified electrician or the local electrical code for specific requirements based on the installation conditions.
A voltage needs to be stated. Assuming the question is from North America 120 volts will be used. Assuming that the 800 watts is for each outlet that is a total of 2400 watts. The electrical code states that a conductor in continuous use can only be loaded to 80% capacity. I = W/E = 2400/120 = 20 amps. A #14 conductor is rated at 15 amps x 80% = 12 amps. A #10 conductor is rated at 30 amps x 80% = 24 amps. So to answer the question, no a 14 gauge wire and a 15 amp breaker will not handle 3 outlets using 800 watts.
Oh, dude, okay, let's break it down. So, to decrease 800 by 15 percent, you just need to multiply 800 by 0.15 (which is 15 percent in decimal form) and subtract that from 800. So, 800 - (800 * 0.15) = 680. So, the answer is 680. Easy peasy, right?
15% of 800= 15% * 800= 0.15 * 800= 120
120 is 15% of 800
A gigantic expensive cable run of #8 gauge wire to a 3:1 transformer.