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What is the Sum of first n natural numbers?
int sum = 0; int i; for(i = 0; i < n; ++i) { sum += i; }
What is the formula to find sum of n even numbers?
Sum = n/2[2Xa1+(n-1)d] where n is last number, a1 is the first number & d is the common difference between the numbers, here d=2 for the even /odd numbers. Sum = n/2 [2Xa1+(n-1)2]
Create a program that will display the sum of all numbers from 1 up to the input number?
to print the sum of first ten numbers:- void main() {int i,sum; sum=0; while(i<=10) sum=sum+i; i=i+1; } printf("The sum is : %d",sum); }
What is the Program to find sum of natural number using recursion?
#include #define NUM 100 //since prog is to be written for adding 100 naturalint main(){int i,sum=0;for(i=1;i
Write algorithm compute sum of square of N numbers?
Oh, what a lovely question! To compute the sum of the squares of N numbers, you can create a simple algorithm. Start by initializing a variable to hold the sum, then loop through each number, square it, and add it to the sum. Once you've done this for all N numbers, you'll have the sum of their squares. Just like painting a happy little tree, take your time and enjoy the process.
