the answer would be...13.98922974, which of course needs to be simplified. i actually had a similar equation to this except with different numbers. you need to use tangent to figure this out.
A simple angle of elevation problem...You want to find out the height of a tree. You measure the distance from you to the base and find that it is 100 feet. You measure the angle of elevation of the top and find that it is 30 degrees. You are six feet tall. How tall is the tree?Answer: The tree is 64 feet tall. Its height is tangent 30 times 100 + 6.
Tan60= 25/Height. Height = 25/Tan60 = 14.43
Providing that the pole is on level ground you have the outline of a right angled triangle with an adjacent side of 92 ft (the shadow of the pole) and a opposite side of 60 ft (the height of the pole). To find the angle of elevation use the tangent ratio. Tangent = Opposite/Adjacent Tangent = 60/92 = 0.652173913 Tan-1(0.652173913) = 33.11134196 degrees Therefore the angle of elevation is 33o correct to two significant figures.
Use the tangent ratio: 23*tan(23) = 9.762920773 Answer: 10 meters to the nearest meter
9.3
i dont care about math even though i use it.
Using trigonometery if you know the length of its shadow and angle of elevation
Angle of elevation: tangent angle = opposite/adjacent and by rearranging the given formula will help to solve the problem
A simple angle of elevation problem...You want to find out the height of a tree. You measure the distance from you to the base and find that it is 100 feet. You measure the angle of elevation of the top and find that it is 30 degrees. You are six feet tall. How tall is the tree?Answer: The tree is 64 feet tall. Its height is tangent 30 times 100 + 6.
Using the formula: tangent = opposite/adjacent whereas tangent angle = height/ground distance, will help to solve the problem
Tan60= 25/Height. Height = 25/Tan60 = 14.43
the angle of elevation would be the angle between the horizon and the line of sight to whatever object you are measuring to. Lets say for instance that you see a plane, and you determine that it has an angle of elevation of 30 deg. This means that from the horizon, you would need to look up at an angle of 30 degrees to see that plane. below I linked to a diagram which illustrates it quite well. Hope this helped!
The language of the question is too ambiguous. In mathematics, we use precise language to avoid this problem. point a is 40 metres from the base of building B the angle of elevation to the top of building C is 51 degree and to the top of the flagpole D on top of building is 56 dedree
The angle of depression of a point is the angle between the line joining that point and the point of observation and the horizontal from the point of observation.
Providing that the pole is on level ground you have the outline of a right angled triangle with an adjacent side of 92 ft (the shadow of the pole) and a opposite side of 60 ft (the height of the pole). To find the angle of elevation use the tangent ratio. Tangent = Opposite/Adjacent Tangent = 60/92 = 0.652173913 Tan-1(0.652173913) = 33.11134196 degrees Therefore the angle of elevation is 33o correct to two significant figures.
A point has coordinates; an angle does not.
two vertical poles of equal height stand on either of a roadway wich is 20 ft wide. At a point in the roadway b/n the poles, the elevation of the taps of the poles are 30 degree and 60 degree. Find the height of the poles?