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No, I think 5 diagonals would be the maximum from a particular vertex. Let's label the vertices [A through H].

For this example, they go clockwise, starting with A and going around to H, so looking at A: B & H are adjacent and both of the segments AB and AH are actually sides of the octagon, not diagonals. The remaining diagonals, from A are:

  1. AC
  2. AD
  3. AE
  4. AF
  5. AG
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Q: Can 6 diagonals be drawn from one vertex of an octagon?
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