Q: Distance between point A 5 7 and point B 2 4?

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Since they are the same point, the distance between them is 0.

Distance = sqrt [(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt [(6 - 4)2 + (- 4 - 0)2]Distance = sqrt [(2)2 + (- 4)2]Distance = sqrt(4 + 16)Distance = sqrt(20)==============

Points: (2, 4) and (5, 0) Distance: 5

There is no difference in the y-coordinates so the distance is simply in the x-coordinates and that is |-4 -4| = |-8| = 8

The distance is 2, along the x-value line x=3 i.e. (3, y).

Related questions

What is the distance between (4, -2) and (-1,6)?

sqrt[(-4 - 4)2 + (-6 - 2)2] = sqrt[82 + 82] = sqrt(64 + 64] = sqrt(128) = 11.31 approx

If you mean points of (5, 5) and (1, 5) then the distance is 4

What is the distance between (4, -2) and (-1,6)?

Since they are the same point, the distance between them is 0.

What is the distance between (4, -2) and (-1,6)?

The distance between the starting point and the destination is 143mi, (230km), and will take approximately 2 hours 4 minutes of driving time.

It is the square root of (-6-4)2+(1-3)2 = 2 times sq rt of 26 or about 10.198 to 3 decimal places

Using Pythagoras: distance = √(change_in_x2 + change_in_y2) = √((5 - -8)2 + (4 - 4)2) = √(132 + 02) = √(132) = 13 units.

Distance = sqrt [(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt [(6 - 4)2 + (- 4 - 0)2]Distance = sqrt [(2)2 + (- 4)2]Distance = sqrt(4 + 16)Distance = sqrt(20)==============

Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.

(0, 4) and (- 4, 6) ???Distance = sqrt[(Y2 - Y1)2 + (X2 - X1 )2]Distance = sqrt[(6 - 4)2 + (- 4 - 0)2]Distance = sqrt( 4 + 16)Distance = sqrt(20)==============