|AB| = sqrt[(5 - 2)2 + (7 - 4)2] =sqrt[9 + 9] = 3*sqrt(2)
Since they are the same point, the distance between them is 0.
Distance = sqrt [(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt [(6 - 4)2 + (- 4 - 0)2]Distance = sqrt [(2)2 + (- 4)2]Distance = sqrt(4 + 16)Distance = sqrt(20)==============
Points: (2, 4) and (5, 0) Distance: 5
The distance is 2, along the x-value line x=3 i.e. (3, y).
There is no difference in the y-coordinates so the distance is simply in the x-coordinates and that is |-4 -4| = |-8| = 8
sqrt[(-4 - 4)2 + (-6 - 2)2] = sqrt[82 + 82] = sqrt(64 + 64] = sqrt(128) = 11.31 approx
What is the distance between (4, -2) and (-1,6)?
If you mean points of (5, 5) and (1, 5) then the distance is 4
What is the distance between (4, -2) and (-1,6)?
Since they are the same point, the distance between them is 0.
To find point A', which is the transformed point, you first determine the distance from point A (3, 4) to the line x = 2. The distance is the horizontal distance, which is |3 - 2| = 1 unit. Since point A' must be the same distance from the line, it can be located either at (1, 4) or (5, 4), depending on whether it is to the left or right of the line x = 2.
What is the distance between (4, -2) and (-1,6)?
The distance between the starting point and the destination is 143mi, (230km), and will take approximately 2 hours 4 minutes of driving time.
It is the square root of (-6-4)2+(1-3)2 = 2 times sq rt of 26 or about 10.198 to 3 decimal places
Using Pythagoras: distance = √(change_in_x2 + change_in_y2) = √((5 - -8)2 + (4 - 4)2) = √(132 + 02) = √(132) = 13 units.
Distance = sqrt [(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt [(6 - 4)2 + (- 4 - 0)2]Distance = sqrt [(2)2 + (- 4)2]Distance = sqrt(4 + 16)Distance = sqrt(20)==============
The distance between the origin (0, 0) and the point (4, -6) can be calculated using the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Substituting the coordinates, we get ( d = \sqrt{(4 - 0)^2 + (-6 - 0)^2} = \sqrt{16 + 36} = \sqrt{52} ). Rounding to two decimal places, the distance is approximately 7.21.