sqrt[(-4 - 4)2 + (-6 - 2)2] = sqrt[82 + 82] = sqrt(64 + 64] = sqrt(128) = 11.31 approx
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
(8-2)2+(-4-15)2 = 397 and the square root of this is the distance which is 19.925 rounded to 3 decimal places
The perpendicular distance from (2, 4) to the equation works out as the square root of 20 or 2 times the square root of 5
It is false-apex
6?! 1-2 2-3 3-4 4-5 5-6 6-7
What is the distance between (4, -2) and (-1,6)?
|AB| = sqrt[(5 - 2)2 + (7 - 4)2] =sqrt[9 + 9] = 3*sqrt(2)
If you mean points of (5, 5) and (1, 5) then the distance is 4
What is the distance between (4, -2) and (-1,6)?
Since they are the same point, the distance between them is 0.
To find point A', which is the transformed point, you first determine the distance from point A (3, 4) to the line x = 2. The distance is the horizontal distance, which is |3 - 2| = 1 unit. Since point A' must be the same distance from the line, it can be located either at (1, 4) or (5, 4), depending on whether it is to the left or right of the line x = 2.
What is the distance between (4, -2) and (-1,6)?
The distance between the starting point and the destination is 143mi, (230km), and will take approximately 2 hours 4 minutes of driving time.
It is the square root of (-6-4)2+(1-3)2 = 2 times sq rt of 26 or about 10.198 to 3 decimal places
Using Pythagoras: distance = √(change_in_x2 + change_in_y2) = √((5 - -8)2 + (4 - 4)2) = √(132 + 02) = √(132) = 13 units.
Distance = sqrt [(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt [(6 - 4)2 + (- 4 - 0)2]Distance = sqrt [(2)2 + (- 4)2]Distance = sqrt(4 + 16)Distance = sqrt(20)==============
The distance between the origin (0, 0) and the point (4, -6) can be calculated using the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Substituting the coordinates, we get ( d = \sqrt{(4 - 0)^2 + (-6 - 0)^2} = \sqrt{16 + 36} = \sqrt{52} ). Rounding to two decimal places, the distance is approximately 7.21.