Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
(8-2)2+(-4-15)2 = 397 and the square root of this is the distance which is 19.925 rounded to 3 decimal places
The perpendicular distance from (2, 4) to the equation works out as the square root of 20 or 2 times the square root of 5
6?! 1-2 2-3 3-4 4-5 5-6 6-7
It is false-apex
What is the distance between (4, -2) and (-1,6)?
If you mean points of (5, 5) and (1, 5) then the distance is 4
|AB| = sqrt[(5 - 2)2 + (7 - 4)2] =sqrt[9 + 9] = 3*sqrt(2)
What is the distance between (4, -2) and (-1,6)?
Since they are the same point, the distance between them is 0.
What is the distance between (4, -2) and (-1,6)?
The distance between the starting point and the destination is 143mi, (230km), and will take approximately 2 hours 4 minutes of driving time.
It is the square root of (-6-4)2+(1-3)2 = 2 times sq rt of 26 or about 10.198 to 3 decimal places
Using Pythagoras: distance = √(change_in_x2 + change_in_y2) = √((5 - -8)2 + (4 - 4)2) = √(132 + 02) = √(132) = 13 units.
Distance = sqrt [(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt [(6 - 4)2 + (- 4 - 0)2]Distance = sqrt [(2)2 + (- 4)2]Distance = sqrt(4 + 16)Distance = sqrt(20)==============
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
(0, 4) and (- 4, 6) ???Distance = sqrt[(Y2 - Y1)2 + (X2 - X1 )2]Distance = sqrt[(6 - 4)2 + (- 4 - 0)2]Distance = sqrt( 4 + 16)Distance = sqrt(20)==============