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To find the equation of the line containing the points (-5, 11) and (3, 4), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we get ( m = \frac{4 - 11}{3 - (-5)} = \frac{-7}{8} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with point (-5, 11), the equation becomes ( y - 11 = -\frac{7}{8}(x + 5) ). Simplifying, the equation of the line is ( y = -\frac{7}{8}x + \frac{33}{8} ).
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What is the equation of the line segment whose end points are at 2 3 and 11 13 on the Cartesian plane showing work?
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9y = 10x+7
What is an equation of a line passing through (25) and (-41)?
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
What is the equation for this line 0-2 20 42?
Points: (0, -2) and (20, 42) Slope: 11/5 Equation: 5y = 11x-10 or as y = 2.2x-2.
What is the equation and its perpendicular bisector equation of the line whose end points are at -2 3 and 1 -1 on the Cartesian plane?
Points: (-2, 3) and (1, -1) Midpoint: (-0.5, 1) Slope: -4/3 Perpendicular slope: 4/3 Equation: 3y = -4x+1 Perpendicular bisector equation: 4y = 3x+5.5
What is the equation of a line that passes through the point -3 -11 and is parallel to the line whose equation is 2x-y equals 4?
The equation of a parallel line is of the form 2x - y = c for some c. (-3, -11) is on this lime so 2*(-3) - (-11) = c -6 + 11 = c so that c = 5 and therefore, the equation is 2x - y = 5
What is the equation of the line that passes through 1 5 and 4 11?
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
What is the equation of the line whose coordinates are at 2 3 and 11 13?
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9x = 10x+7
What is the equation of the line segment whose end points are at 2 3 and 11 13 on the Cartesian plane showing work?
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9y = 10x+7
What is the equation of the line in point-slope form that passes through the points -1 7 and -2 3?
Points: (-1, 7) and (-2, 3) Slope: 4 Equation: y = 4x+11
What is an equation of a line passing through (25) and (-41)?
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
What is the equation for this line 0-2 20 42?
Points: (0, -2) and (20, 42) Slope: 11/5 Equation: 5y = 11x-10 or as y = 2.2x-2.
Which of the following points are on the line given by the equation y equals -3x plus 5?
(-2, 11)(-3, 14)(2, -1)
What is the equation of the line whose intercepts are x is 7 and y is 11 showing work?
Points: (7, 0) and (0, 11) Slope: 0-11/7-0 = -11/7 Equation: y-0 = -11/7(x-7) => 7y = -11x+77 Equation: y-11 = -11/7(x-0) => 7y = -11x+77
What is x plus y equals 11?
It is an equation of a straight line.
What is the equation of a line through 1 11 and -2 2?
To find the equation of a line passing through two points, we first calculate the slope using the formula (y2 - y1) / (x2 - x1). Given the points (1, 11) and (-2, 2), the slope is (2 - 11) / (-2 - 1) = -9 / -3 = 3. Next, we use the point-slope form of a linear equation, y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Substituting (1, 11) as the point and 3 as the slope, we get the equation y - 11 = 3(x - 1). Simplifying, we get y = 3x + 8 as the equation of the line.
Which is the equation of a trend line that passes through the points (3 95) and (11 12) Round values to the nearest ten-thousandths.?
Y=_10.35x+126.125
What is the equation for a line that goes through points 611 and 310?
Given points: (6, 11), (3, 10)Find: the equation of the line that passes through the given points Solution: First, wee need to find the slope m of the line, and then we can use one of the given points in the point-slope form of the equation of a line. After that you can transform it into the general form of the equation of a line. Let (x1, y1) = (3, 10), and (x2, y2) = (6, 11) slope = m = (y2 - y1)/(x2 - x1) = (11 - 10)/(6 - 3) = 1/3 (y - y1) = m(x - x1)y - 10 = (1/3)(x - 3)y - 10 = (1/3)x - 1y - 10 + 10 - (1/3)x = (1/3)x - (1/3)x + 10 - 1-(1/3)x + y = 9 which is the general form of the required line.
