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To find the equation of the line containing the points (-5, 11) and (3, 4), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we get ( m = \frac{4 - 11}{3 - (-5)} = \frac{-7}{8} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with point (-5, 11), the equation becomes ( y - 11 = -\frac{7}{8}(x + 5) ). Simplifying, the equation of the line is ( y = -\frac{7}{8}x + \frac{33}{8} ).
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What is the equation of the line segment whose end points are at 2 3 and 11 13 on the Cartesian plane showing work?
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9y = 10x+7
What is an equation of a line passing through (25) and (-41)?
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
What is the equation for this line 0-2 20 42?
Points: (0, -2) and (20, 42) Slope: 11/5 Equation: 5y = 11x-10 or as y = 2.2x-2.
What is the equation and its perpendicular bisector equation of the line whose end points are at -2 3 and 1 -1 on the Cartesian plane?
Points: (-2, 3) and (1, -1) Midpoint: (-0.5, 1) Slope: -4/3 Perpendicular slope: 4/3 Equation: 3y = -4x+1 Perpendicular bisector equation: 4y = 3x+5.5
What is the equation of the line of best fit for the following data . x y 2 2 5 8 7 10 9 11 11 13?
To find the equation of the line of best fit for the given data points (2, 2), (5, 8), (7, 10), (9, 11), and (11, 13), we can use the least squares method. The calculated slope (m) is approximately 0.85 and the y-intercept (b) is around 0.79. Thus, the equation of the line of best fit is approximately ( y = 0.85x + 0.79 ).
What is the equation of the line that passes through 1 5 and 4 11?
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
What is the equation of the line whose coordinates are at 2 3 and 11 13?
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9x = 10x+7
What is the equation of the line segment whose end points are at 2 3 and 11 13 on the Cartesian plane showing work?
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9y = 10x+7
What is the equation of the line in point-slope form that passes through the points -1 7 and -2 3?
Points: (-1, 7) and (-2, 3) Slope: 4 Equation: y = 4x+11
What is an equation of a line passing through (25) and (-41)?
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
What is the equation for this line 0-2 20 42?
Points: (0, -2) and (20, 42) Slope: 11/5 Equation: 5y = 11x-10 or as y = 2.2x-2.
Which of the following points are on the line given by the equation y equals -3x plus 5?
(-2, 11)(-3, 14)(2, -1)
What is the equation of the line whose intercepts are x is 7 and y is 11 showing work?
Points: (7, 0) and (0, 11) Slope: 0-11/7-0 = -11/7 Equation: y-0 = -11/7(x-7) => 7y = -11x+77 Equation: y-11 = -11/7(x-0) => 7y = -11x+77
What is x plus y equals 11?
It is an equation of a straight line.
What is the equation of a line through 1 11 and -2 2?
To find the equation of a line passing through two points, we first calculate the slope using the formula (y2 - y1) / (x2 - x1). Given the points (1, 11) and (-2, 2), the slope is (2 - 11) / (-2 - 1) = -9 / -3 = 3. Next, we use the point-slope form of a linear equation, y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Substituting (1, 11) as the point and 3 as the slope, we get the equation y - 11 = 3(x - 1). Simplifying, we get y = 3x + 8 as the equation of the line.
Which is the equation of a trend line that passes through the points (3 95) and (11 12) Round values to the nearest ten-thousandths.?
Y=_10.35x+126.125
What is the equation for a line that goes through points 611 and 310?
Given points: (6, 11), (3, 10)Find: the equation of the line that passes through the given points Solution: First, wee need to find the slope m of the line, and then we can use one of the given points in the point-slope form of the equation of a line. After that you can transform it into the general form of the equation of a line. Let (x1, y1) = (3, 10), and (x2, y2) = (6, 11) slope = m = (y2 - y1)/(x2 - x1) = (11 - 10)/(6 - 3) = 1/3 (y - y1) = m(x - x1)y - 10 = (1/3)(x - 3)y - 10 = (1/3)x - 1y - 10 + 10 - (1/3)x = (1/3)x - (1/3)x + 10 - 1-(1/3)x + y = 9 which is the general form of the required line.
