Q: Find the slope of the line that passes through the points 0 0 and 2 4?

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y=mx+b

Assume your points are (x1, y1) and (x2, y2). The slope of a line is its rise (the change in y-coordinates) over its run (the change in x-coordinates). So to find the slope of the line, you substitute the correct values into the formula (y2 - y1) / (x2 - x1).

(0,5).

slope = change_in_y/change_in_x = (-1 - 2)/(8 - 5) = -3/3 = -1

The "point slope" formula would be used. This is Y-Y1=m(X-X1) where Y1 and X1 are points the line passes through. M is the slope, so to find the slope of a line perpendicular, take it's opposite reciprocal which would be -8x/9. So Y-(-8)=-8/9(X-18) distribute -8/9 into X-18 and add the 8 on the left side of the = to get the slope intercept form.

Related questions

y=mx+b

1

No

1

2222

Not always. For example, try to find the slope of the line that passes through the points (3, 4) and (2, 3).

To find the slope of a line passing through two points, use the formula (y2 - y1) / (x2 - x1). In this case, the two points are (17, 101). Since there is only one given point, it is not possible to find the slope of the line passing through these points.

It is a straight line with no slope with a 'y' intercept of 2

Slope, m, equals (y2-y1)/(x2-x1). Slope is (8-2)/(8-2) or 1.

Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.

The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.

It's not possible because the given points would be a vertical line parallel to the y axis