Slope, m, equals (y2-y1)/(x2-x1). Slope is (8-2)/(8-2) or 1.
To find the slope of a line passing through two points, use the formula (y2 - y1) / (x2 - x1). In this case, the two points are (17, 101). Since there is only one given point, it is not possible to find the slope of the line passing through these points.
It is a straight line with no slope with a 'y' intercept of 2
Another set of points are needed to find the slope.
To find the slope of the line that passes through the points (-5, 2) and (2, 3), use the slope formula: ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Here, ( (x_1, y_1) = (-5, 2) ) and ( (x_2, y_2) = (2, 3) ). Plugging in these values gives ( m = \frac{3 - 2}{2 - (-5)} = \frac{1}{7} ). Thus, the slope of the line is ( \frac{1}{7} ).
That depends on the points in order to find the slope whereas no points have been given.
y=mx+b
1
No
2
1
Not always. For example, try to find the slope of the line that passes through the points (3, 4) and (2, 3).
To find the slope of a line passing through two points, use the formula (y2 - y1) / (x2 - x1). In this case, the two points are (17, 101). Since there is only one given point, it is not possible to find the slope of the line passing through these points.
It is a straight line with no slope with a 'y' intercept of 2
Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.
The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.
It's not possible because the given points would be a vertical line parallel to the y axis
Another set of points are needed to find the slope.