You can do it by memorizing this statement:
" The sum of the exterior angles of every polygon is 360 degrees. "
Given a shape as such... ______________________________________ / A=72 B=65 \ \ / \_C=105__________________D=110_______/ (sorta) You take the interior angles that you have and subtract them from 360 to get their supplementary angles, which would be the measure of the outside angles corresponding to the interior angles Measure of <A= 72- so 360- 72=288*; so the measure of the exterior angle corresponding to <A is 288* You can do the same thing for the rest of the angles in the polygon. Hope it helps...
sum of exterior angles in a polygon is always equal to 3600,sum of all the interior angles is given by (n-2)1800, where n is the number of sides of the polygon.According to the question,(n-2)1800=2(3600)n-2=4so n=6answer:6
The measure of an interior angle in degrees of a regular polygon of n sides is given by the formula: 180 x (n-2) / nSubstituting with n=18, then the answer is that the interior angle = 160The measure of an exterior angle in degrees of a regular polygon of n sides is given by the formula: 360/nSubstituting with n= 18, then the answer is that the exterior angle = 20
A rhombus would fit the given description.
# Any exterior angle of a polygon corresponds to an interior angle, and their sum is 180 degrees. # If there are n sides (and therefore n vertices) then the sum of all the interior and exterior angles must be 180n. # The external angles of a polygon total 360 degrees, else it could not be a closed shape. # From the above three points, it follows that the sum of interior angles is given by 180n - 360. So, if there is an integer solution to 180n - 360 = 180(n - 2) = 5400, then the answer to your question is yes. 180(n - 2) = 5400 n - 2 = 30 n = 32 A polygon with 32 sides fulfills the criterion. That would be, hmmm, a triacontakaidigon, of course.
360o; the sum of the exterior angles of any polygon is 360, as given in the formula E = 360.
There isn't one. The sum of the exterior angles is always 360 degrees, the sum of the interior angles varies depending on the number of sides.
To find the sum of the interior angles and the sum of the exterior angles of any polygon. To review linear measurement to the nearest sixteenth of an inch and angle measurement to the nearest degree. To construct a polygon and its exterior angles given the number of sides. hope this helped
The sum total of all exterior angles of any polygon is 360 degrees. So if you're given thevalue of one exterior angle AND THE POLYGON IS REGULAR(all exterior angles are thesame size), all you have to do is divide the size of one angle into 360, and the quotientis the number of sides.
The sum of the interior angles of any polygon is equal to (n-2) * 180 degrees, where n is the number of sides of the polygon. Since the exterior angles of a polygon are supplementary to the interior angles, if the exterior angles are 24 degrees, the interior angles would be 180 - 24 = 156 degrees.
The two numbers are the same.
If you mean exterior angle is twice its interior angle then an equilateral triangle will fit the given description because each interior angle is 60 degrees and each exterior angle is 120 degrees
For any given polygon, the exterior angles will sum to 360 degrees. Thus, for a regular polygon, dividing by the number of exterior angles (the same as the number of sides) will produce the exterior angle. For a dodecagon (12 sides), 360/12=30 degrees. You can also find the interior angle easily because the interior and exterior angles are supplementary: 180-30=150 degrees for an interior angle.
Given a shape as such... ______________________________________ / A=72 B=65 \ \ / \_C=105__________________D=110_______/ (sorta) You take the interior angles that you have and subtract them from 360 to get their supplementary angles, which would be the measure of the outside angles corresponding to the interior angles Measure of <A= 72- so 360- 72=288*; so the measure of the exterior angle corresponding to <A is 288* You can do the same thing for the rest of the angles in the polygon. Hope it helps...
By dividing the given exterior angle into 360 degrees tells you how many sides the polygon has.
sum of exterior angles in a polygon is always equal to 3600,sum of all the interior angles is given by (n-2)1800, where n is the number of sides of the polygon.According to the question,(n-2)1800=2(3600)n-2=4so n=6answer:6
The measure of an interior angle in degrees of a regular polygon of n sides is given by the formula: 180 x (n-2) / nSubstituting with n=18, then the answer is that the interior angle = 160The measure of an exterior angle in degrees of a regular polygon of n sides is given by the formula: 360/nSubstituting with n= 18, then the answer is that the exterior angle = 20