If you have a function f(x), then the tangent can be found by deriving f, denoted
d/dx(f(x)) = f'(x). This will give the slope of f(x) at a certain point (a,b).
find f'(a), call this m. Now, use the standard form for a line, y = mx+c, plug in the point (a,b) to solve for c. Finally, the equation for the line tangent to a point (a,b) and f(x) is y= f'(a)x + c
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Take the inverse tangent -- tan-1(opposite side/adjacent side)
Not enough information has been given to find the tangent BC but it will be perpendicular or at right angles to the radius of the circle.
Use a calculator. There is no simple way to calculate it.
its the tangent of the angle the slope makes with the x-axis
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