Its diameter is 2R, whatever the mass.
I believe it is I = mk^2 where k is radius of gyration and m is mass.
Basically radius of gyration of a substance is defined as that distance from the axis of rotation from which if equivalent mass that of the substance is kept will have exactly the same moment of inertia about that axis of the substance.
Provided they are the same thickness, the larger sphere will have a radius of 10.165cm
Volume of a sphere = 4/3*pi*radius3 Surface area of a sphere = 4*pi*radius2
i will be twice as heavy
(1/2)mr^2 where m=mass r=radius
mass moment of inertia for a solid sphere: I = (2 /5) * mass * radius2 (mass in kg, radius in metres)
The moment of inertia of a hollow cylinder can be calculated with the help of the formula, I=0.5xMxRxR. Here I is inertia, M is mass and R is the radius.
I believe it is I = mk^2 where k is radius of gyration and m is mass.
.00288 kgm^2
It is the square root of ratio moment of inertia of the given axis to its mass.
Moment of inertia depends upon the distribution of mass with respect to the axis of rotation.The greater the distance between the bulk of an object's mass and the axis of rotation, the greater the moment of inertia will be. A solid disk has its mass distributed evenly across its diameter, while a ring has its mass concentrated furthest from the centre of rotation.
mass moment of inertia is the property of the body to resist rotation about the given axis where as the area moment of inertia is the resistance to bending about the given axis
Moment of Inertia of a disk (I) = 1/2MR2 Moment of Inertia of a disk (I) = 1/4MR2
It can be done, but it would require taking an integral for the moment of inertia of each particle of the disc... something i don't have the time to do right now ^^;
mass, velocity and radius
Rotated about a line on the surface ? I = Mass * radius2 . Rotated about a line through the centre : I = (2 * mass * radius2) / 5