Assume your points are (x1, y1) and (x2, y2). The slope of a line is its rise (the change in y-coordinates) over its run (the change in x-coordinates).
So to find the slope of the line, you substitute the correct values into the formula (y2 - y1) / (x2 - x1).
y=mx+b
2
(0,5).
slope = change_in_y/change_in_x = (-1 - 2)/(8 - 5) = -3/3 = -1
The "point slope" formula would be used. This is Y-Y1=m(X-X1) where Y1 and X1 are points the line passes through. M is the slope, so to find the slope of a line perpendicular, take it's opposite reciprocal which would be -8x/9. So Y-(-8)=-8/9(X-18) distribute -8/9 into X-18 and add the 8 on the left side of the = to get the slope intercept form.
y=mx+b
1
No
2
1
Not always. For example, try to find the slope of the line that passes through the points (3, 4) and (2, 3).
To find the slope of a line passing through two points, use the formula (y2 - y1) / (x2 - x1). In this case, the two points are (17, 101). Since there is only one given point, it is not possible to find the slope of the line passing through these points.
It is a straight line with no slope with a 'y' intercept of 2
Slope, m, equals (y2-y1)/(x2-x1). Slope is (8-2)/(8-2) or 1.
To find the slope of the line that passes through the points ((a-b)) and ((-a-b)), we first clarify that these points are actually ((a, -b)) and ((-a, -b)). The slope (m) is calculated using the formula (m = \frac{y_2 - y_1}{x_2 - x_1}). Substituting the points, we have (m = \frac{-b - (-b)}{-a - a} = \frac{0}{-2a} = 0). Thus, the slope of the line is 0, indicating a horizontal line.
To find the slope of the line that passes through the points (9, -81) and (6, -36), use the formula for slope ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Plugging in the values, we have ( m = \frac{-36 - (-81)}{6 - 9} = \frac{45}{-3} = -15 ). Thus, the slope of the line is -15.
Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.