It is the square root of (x1-x2)^2 + (y1-y2)^2
So that you can plot out the points of a straight line on graph paper.
Points: (0, 1) and (1, 0) Slope: -1 Equation: y = -x+1 Distance: square root of 2
In coordinated geometry the points on a straight line will determine its equation.
It is the locus of all points whose coordinates satisfy the equation of the line.
But it's not an equation because there is no equal sign and no points are given.
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
To find the perpendicular distance between two points, you can use the distance formula and the concept of perpendicular lines. First, calculate the distance between the two points using the distance formula. Then, find the slope of the line passing through the two points. The perpendicular distance is the length of the line segment that connects the two points and forms a right angle with the line passing through them.
So that you can plot out the points of a straight line on graph paper.
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
Points: (0, 1) and (1, 0) Slope: -1 Equation: y = -x+1 Distance: square root of 2
In coordinated geometry the points on a straight line will determine its equation.
. the equation of a straight line can be found by using two points on a line . First find the gradient of the line using the gradient formula . now substitute the gradient into general form replacing "m" . use one of the points and substitute into equation to solve "c" example 1: find the equation of the line which passes through the points (1,3) and (2,5). step 1: find the gradient M=5-3/2-1=2 (/=divide) step 2: place m into the equation Y=2x+c step 3: substitute point into equation 3=2(1)+c step 4: solve C=1 equation is Y=2x+1 hope that helps :)
Assuming you want the equation of the straight line between the two points (x0, y0) and (x1, y1), the equation is: y - y0 = m(x - x0) where m is the gradient between the two points: m = (y1 - y0) ÷ (x1 - x0) Note: if the two x coordinates are equal, that is x0 = x1, then the equation of the line is x = x0.
The answer will depend on the equation of the line.
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
It is the locus of all points whose coordinates satisfy the equation of the line.