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Using Pythagoras' theorem it is 40 feet
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Diagonal measurement of a rectangal?
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
What is the area of a rectangle 4m long and 200cm wide?
32 metres
What is the of a rectangle area of 8 inches long and 4 inches wide?
32 square inches.
A side of a square has length 3 what is the length of its diagonal?
Use Pythagoras' therom: 32+32 = 18 The square root of 18 is 4.242640687 units which is the length of the diagonal.
What is the length and width for a rectangle with a perimeter of 32?
8 length 8 width
What is the dimensions of a rectangle for the number 32?
It is not possible to answer the question because you have not defined what 32 measures: is it the area of the rectangle, its perimeter, its diagonal or some other property?
The length and width of a rectangle are 8 inches and 4 inches respectively What would be the area of one of the triangles formed from drawing a diagonal in the rectangle?
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
How do you find the diagonal of a rectangle?
By the Pythagorean Theorem, the diagonal is the hypotenuse of the right triangle formed by the diagonal and the two included sides. c2 = a2 + b2 so the diagonal is the square root of the sum of the squares of the rectangle's length and width. Example : for a rectangle 4 x 3, the diagonal is sqrt(32 + 42) = sqrt (25) = 5
What is length of diagonal line in rectangle 32 feet by 36 feet?
Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal
What is the length of a rectangle whose diagonal is 32 inch?
The diagonal of a rectangle does not provide enough information to determine the length of the rectangle. Let L be any real number such that 32/sqrt(2) < L < 32. let B = sqrt(32^2 - L^2) Since L < 32 the above square root exists, and since L > 32/sqrt(2), B < L. So the rectangle with sides of L and B will have a diagonal of 32 inches. But L is any of an infinite number of possible real numbers. Therefore there are infinitely many possible solutions.
Diagonal measurement of a rectangal?
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
What is the length of a diagonal in a 3cm times 2cm rectangle?
By Pythagoras, diagonal = sqrt(32 + 22) = sqrt(9 + 4) = sqrt(13) = 3.606 cm (approx)
What is the length of the diagonal of a rectangle with adjacent sides measuring 3 cm and 8 cm?
32 + 82 = diagonal2 (9 + 64) = 8.544
How do you find the length of a rectangle knowing ONLY the diagonal and the length?
If by that you mean knowing only the diagonal and the width, then by the formula a2+b2=c2, where a is the length, b the width and c the diagonal. To find the width b, you need to calculate sqrt(c2-a2). For example, the width of a rectangle with length 3 and diameter 5 is sqrt(52-32)=4
What is the diagonal of a rectangle 32 ft. by 16 ft.?
Using Pythagoras, Diagonal2 = 322 + 162 = 162*(4 + 1) = 162*5 So diagonal = 16*sqrt(5) = 35.7771 ft (to 4 dp)
What is the area of a rectangle 4m long and 200cm wide?
32 metres
What is the diagnal of a rectangle 8m x 3m?
Use Pythagoras' theorem:- 82+32 = 73 and the square root of this is length of the diagonal which is about 8.544m to 3 decimal places
