A diagonal line of a polygon is a line that joins any two vertices not already joined by a side. A polygon with n sides has n(n-3)/2 diagonals → a decagon has 10(10-3)/2 = 10 × 7 ÷ 2 = 35 diagonals
35
It depends if the polygon is convex or concave but if it is a regular polygon it would have 560
It will have 35 sides and can be described as a 35-agon
A 35-sided polygon.
To determine the number of triangles in a 35-gon, we can use the formula n(n-1)(n-2)/6, where n is the number of vertices in the polygon. In this case, a 35-gon has 35 vertices, so the formula becomes 35(35-1)(35-2)/6. Simplifying this expression, we get 353433/6 = 6545 triangles in a 35-gon.
The formula to calculate the number of diagonals in a polygon is n(n-3)/2, where n represents the number of vertices. Setting this formula equal to 560 and solving for n, we get n(n-3)/2 = 560. By solving this quadratic equation, we find that the polygon has 20 vertices.
There are 560 diagonals by using the diagonal formula
A diagonal line of a polygon is a line that joins any two vertices not already joined by a side. A polygon with n sides has n(n-3)/2 diagonals → a decagon has 10(10-3)/2 = 10 × 7 ÷ 2 = 35 diagonals
35
35.
35 sides
It has 35 diagonals
It will have ten sides
It depends if the polygon is convex or concave but if it is a regular polygon it would have 560
(35*(35-3))/2 (35*32)/2 1120/2 560 diagonals
It has 35 sides.