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Q: The area of the triangle above is 21. What is the value of x?

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13

Area = 0.5*21*28 = 294 square inches

The hypotenuse of 21 does not yield an integral value for the second leg. The legs are 16 and the square root of 185, which is about 13.6 The area of the triangle is 1/2 (16 x 13.6) = about 108.8 212 = 162 + x2 x2 = 185 x = 13.6

(6.06 x 3.5) = 21.20 sq in.

Let the sides of the triangle be abc and their opposite angles be ABC Angle C: (21^2 +20^2 -29^2)/(2*21*20) = 90 degrees by the cosine rule Area: 0.5*21*20*sin(90 degrees) = 210 square cm by the area sine rule Alternatively: 0.5*21*20 = 210 square cm because it is a right angle triangle

Related questions

13

Area = 0.5*21*28 = 294 square inches

Area = 0.5*21*28 = 294 square inches

21.20

The hypotenuse of 21 does not yield an integral value for the second leg. The legs are 16 and the square root of 185, which is about 13.6 The area of the triangle is 1/2 (16 x 13.6) = about 108.8 212 = 162 + x2 x2 = 185 x = 13.6

The area is 294 square inches.

294 in^2

Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.

The lengths of two sides of a triangle do not provide enough information to calculate either its perimeter or its area.

I need to know more about the triangle, such as one or 2 of the angles, whether it is isosceles or equilateral, or whether the lengths share a certain ratio. For example, a triangle of sides 8,8 and 5 (perimeter of 21) will surely have a different area as compared to a triangle of sides 7,7 and 7 (perimeter of 21 as well)

If the area of the triangle is 210 square m and its height is 20 m Then its base is: 21 m Check: 0.5*21*20 = 210 square m

21 inches

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