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i can't help you solve this if i cannot see the triangle. What are the values involved, aside from the area?
Area = 0.5*21*28 = 294 square inches
The hypotenuse of 21 does not yield an integral value for the second leg. The legs are 16 and the square root of 185, which is about 13.6 The area of the triangle is 1/2 (16 x 13.6) = about 108.8 212 = 162 + x2 x2 = 185 x = 13.6
Let the sides of the triangle be abc and their opposite angles be ABC Angle C: (21^2 +20^2 -29^2)/(2*21*20) = 90 degrees by the cosine rule Area: 0.5*21*20*sin(90 degrees) = 210 square cm by the area sine rule Alternatively: 0.5*21*20 = 210 square cm because it is a right angle triangle
(6.06 x 3.5) = 21.20 sq in.
i can't help you solve this if i cannot see the triangle. What are the values involved, aside from the area?
Area = 0.5*21*28 = 294 square inches
Area = 0.5*21*28 = 294 square inches
The hypotenuse of 21 does not yield an integral value for the second leg. The legs are 16 and the square root of 185, which is about 13.6 The area of the triangle is 1/2 (16 x 13.6) = about 108.8 212 = 162 + x2 x2 = 185 x = 13.6
21.20
294 in^2
The area is 294 square inches.
Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.
I need to know more about the triangle, such as one or 2 of the angles, whether it is isosceles or equilateral, or whether the lengths share a certain ratio. For example, a triangle of sides 8,8 and 5 (perimeter of 21) will surely have a different area as compared to a triangle of sides 7,7 and 7 (perimeter of 21 as well)
If the area of the triangle is 210 square m and its height is 20 m Then its base is: 21 m Check: 0.5*21*20 = 210 square m
A triangle cannot have four lengths!
The area of a triangle is half the base multiplied by the vertical height. It doesn't matter which side we take as the base, so I'll use 6. now the height can never be more than 7, so the maximum area is 0.5 x 6 x 7 = 21 square units. slightly better: Area = 0.5 x 7 x 6 sinø where ø is the angle between the sides of length 6 and 7 maximum value of sin ø is 1. => maximum area = 0.5 x 6 x 7 = 21