Area can never be as low as the perimeter value -- impossible question.
No impossible if read correctly...18 meters squared is the area and 18 meters is the perimeter.
Rectangles Perimeter Is 2L + 2W. 2(7) + 2(4) = Perimeter 14 + 8 = Perimeter Perimeter = 22
For rectangles, there are only two side lengths and the perimeter is obviously P = 2 (L + W). For squares, P = 4S. If you know the diagonal length of a rectangle, you only need one side to find the other side length using the Pythagorean theorem (d squared = side a squared + side b squared). If it is a square, knowing the diagonal gives you the perimeter: it is 4 times the square root of (d squared divided by 2). In other more complex figures you will need to use more concepts like parallel lines, perpendicular lines, and other geometric theorems like the Pythagorean theorem.
I don't understand why there are so many questions about rectangles' perimeter. You just add the length and the width and double your answer....
the old perimeter is 17 * 2 The old perimeter = 38
Perimeter is a length, and a length cannot be the same as an area.Ignoring the units, all rectangles that have the same numerical perimeter as area are those that satisfy:2 x (length + width) = length x widthwhich can be rearranged to give:width = 2 x length/(length - 2)Meaning that given any length over 2, a width can be found to give a rectangle that meets the requirement that its numerical perimeter is the same as its numerical area. (For a length greater than 0 and less than 2, the width would be negative and not possible; similarly for a length less than 0, the length is negative and not possible. When the length is 2, the width is undefined and so not possible. When the length is 0 the width is 0 and it is not a rectangle.)At some stage as the length increases, the length will equal the width and as the length continues to increase the rectangle then given will match the previous rectangles with the length and widths swapped. This occurs when:length = 2 x length/(length - 2)⇒ length x (length - 4) = 0⇒ length = 4.So, as long as the length is greater than or equal 4 it will be the longer side - the length, by convention, is the longer side. Thus all rectangles satisfy:width = 2 x length/(length - 2)with length ≥ 4, will have the numerical value of their perimeter the same as the numerical value of their area.For example:4 cm x 4 cm: perimeter = 16 cm, area = 16 cm25 cm x 31/3 cm: perimeter = 162/3 cm, area = 162/3 cm26 cm x 3 cm: perimeter = 18 cm, area = 18 cm241/2 cm x 33/5 cm: perimeter = 161/5 cm, area = 161/5 cm2etcNote: the first example is a square which is a rectangle with all the sides the same length.
No rectangle can have equal perimeter and length.
The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
Rectangles Perimeter Is 2L + 2W. 2(7) + 2(4) = Perimeter 14 + 8 = Perimeter Perimeter = 22
Perimeter: add all sides area: multiply length times width for rectangles
It is: 2(x+y) = perimeter whereas x is the width and y is the length of the rectangle
For rectangles with the same perimeter, the sum of the length and width is constant, as it is directly related to the perimeter formula (P = 2(length + width)). However, even though they share the same perimeter, rectangles can have different areas depending on the specific values of length and width. This means that while the sum of length and width remains unchanged, the individual dimensions can vary to produce different areas.
P=2(L+w) L=length W=width
I don't understand why there are so many questions about rectangles' perimeter. You just add the length and the width and double your answer....
Perimeter = 2 x (width + length)⇒ 12 = 2 x (width + length)⇒ width + length = 6⇒ the rectangles could be:1 by 52 by 43 by 3[A square is a rectangle with equal sides.]
The perimeter is 18 feet.
Pythagorean theorem ~ a Squared + b Squared= c Squared
You can't tell the dimensions from the perimeter. There are an infinite number of different rectangles, all with different lengths and widths, that all have the same perimeter.