It is not possible to answer the question.
Let L be any number greater than 24 units and let B = 24 - L. Then the perimeter of a rectangle with length L and breadth B is
2*(L + B) = 2*(L + 24 - L) = 2*24 = 48.
The choice of L is arbitrary and so there are infinitely many possible solutions.
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what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
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Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.
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