x2-9x can be factored by taking x out of each term x(x-9)
Equation: 10x^2 -29x +10 = 0 When factored: (2x-5)(5x-2) = 0 Its solutions: x = 5/2 or x = 2/5
2m = 26m = 26/2m = 13
74
multiply charges divide by disatance squared. 58*2.1=121.8 121.8/3.2^2=11.8945
1 m^(2) + 1 m^(2) = 2m ^(2)
Well x squared could can be broken down (factored) into x times x. So yes, it can be.
Assuming you mean 2m2... (2m - 3)(m + 4)
m = 9 This is because, if: m squared - 2m - 65 = 2 Then: m squared - 2m = 65 + -2 m squared - 2m = 63 So: 63 = m squared - 2m m squared - 2m = m x m - 2m This means: 63 = m (m - 2) So something times itself minus two is 63. Going through different numbers, it is clear that 9 and 7 work. So: m x (m - 2) = 9 x (9-2) = 9 x (7) = 9 x 7 = 63 M is therefore 9.
It is (x-1)(x-8) when factored
(a - 2b)(2a - b)
64-x2 = (8-x)(8+x) when factored
2x2-1x-120 = (2x+15)(x-8) when factored
It is (A-1)(A+1) when factored
If you mean (1+2x)2, that is already factored.
3x2-39x-90 = (3x+6)(x-15) when factored
r2-r-56 factored out equals (r-8)(r+7).