15.588 square inches.
A triangle with side a: 6, side b: 6, and side c: 6 inches has an area of 15.59 square inches.
The side length is 18.24 (18.23606) inches.
The perimeter of an equilateral triangle with a side length of 4 inches is 12 inches. Each side of an equilateral triangle is equal in length, so the perimeter is found by multiplying the side length (4 inches) by 3.
Assuming that the hexagon is regular (all sides are the same), it can be comprised of 6 equilateral triangles of side length 6 (in this case). Area of a equilateral triangle is: (side length^2*√3)/4 Each triangle is of area: 62.353829072479572 inches square. 62.353829072479572*6 = 374.12297443487743 inches square approx.
3 inches, an equilateral triangle has equal side lengths and angle measures
A triangle with side a: 6, side b: 6, and side c: 6 inches has an area of 15.59 square inches.
12
15.2 inches.
The side length is 15.2 (15.19671) inches.
The side length is 18.24 (18.23606) inches.
Area of Equilateral Triangle A= S2 * (Root 3)/4, where A= Area of the triangle S= Side of the triangle.
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 Times Square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
The perimeter of an equilateral triangle with a side length of 4 inches is 12 inches. Each side of an equilateral triangle is equal in length, so the perimeter is found by multiplying the side length (4 inches) by 3.
I'm showing it with absolute proof. Equilateral triangle both side are same in size & same angel.It's given with the sides of 10 inches & height 7 inches. I don't need to count the height(7),just use side(10).The formula is=Area of a equilateral triangle="root over of 3" /4 * "a square"Now I use this formula,where "a" is 10. So the answers come=43.3,which is 44.So the Correct answer is=44 inches.* * * * *Mostly correct, but:43.3 should be rounded to 43, not 44.The units for the area should be square inches, not inches.
There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.
Assuming that the hexagon is regular (all sides are the same), it can be comprised of 6 equilateral triangles of side length 6 (in this case). Area of a equilateral triangle is: (side length^2*√3)/4 Each triangle is of area: 62.353829072479572 inches square. 62.353829072479572*6 = 374.12297443487743 inches square approx.
3 inches, an equilateral triangle has equal side lengths and angle measures