at a 45 degree angle, or pi/4
0.75
Given an angle A, the angle (2pi - A) has the same cosine. So do the angles that differ from these by 2k*pi radians for all integers k. If you are still working in degrees, you should substitute 180 degrees for pi radians.
The secant of an angle is the reciprocal of the cosine of the angle. So the secant is not defined whenever the cosine is zero That is, whenever the angle is a multiple of 180 degrees (or pi radians).
Sine= Opposite/ Hypotenuse Cosine= Adjacent/ Hypotenuse
It doesn't exist. The maximum value of the cosine is 1.00, so no angle can have a cosine of (pi), because (pi) is more than 3.
Looking at a unit circle, cosine is the horizontal coordinate. Pi radians is halfway around the circle (180°), so the coordinate is (-1,0). Cosine(pi) = -1
udefined
The cosine of 2pi is 1. In fact, for every integer N, the cosine of 2 N pi is 1.
The sine curve is exactly the same as the cosine curve shifted pi/2 radians to the left
Yes, except at odd multiples of pi/2 radians, where the cosine is zero so that the division is not defined.
at a 45 degree angle, or pi/4
0.75
Yes they are. Both have a a period of 2 pi
cos(x) = sin(pi/2-x) = -sin(x-pi/2)
The inverse of the cosine function is arcosine. The domain is −1 ≤ x ≤ 1 since the range of the cosine function is from -1 to 1. The range is from 0 to pi radians or 0 to 180 degrees.
It is the same period as cosine function which is 2 pi because sec x = 1/cos x