17.8885'
There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13
Don't tell me you are in class!
An 8x8 rectangle is either a square, all of whose sides are 8 units long or it can be a rectangles whose opposite sides are 8 units long - but in different measurement units: for example, a rectangle whose sides are 8 centimetres and 8 metres.
-- Every rectangle has four interior right angles.-- Every square is also a rectangle, so the question is describing a total of four rectangles.-- (4 rectangles) x (4 right angles per rectangle) = 16 right angles
Using Pythagoras' theorem it works out as 4 times the square root of 13 which is about 14.422 to 3 decimal places
Around 17.8. I did this with cossin, but check the answer with a calculator
There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13
The diagonal of a rectangle 8 feet by 12 feet is √208 feet, or about 14 feet 5.06 inches.
10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet
The diagonal measurement of an 8 ft square is: 11.31 feet.
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
(Diagonal)2 = (15)2 + (8)2 = (225) + (64) = 289Diagonal = sqrt(289) = 17
Diagonal = 10 meters.
To find the perimeter of a rectangle we need to know the length of its sides. P = 2L + 2W Let L = 8, and W = √(102 - 82) = √(100 - 64) = √36 = 6 (by the Pythagorean theorem, where the hypotenuse is the diagonal and legs are the sides of the rectangle). Thus, P = 2(8) + 2(6) = 16 + 12 = 28.
The square has a diagonal measurement of: 1.13 km
There is no such rectangle.
The room measures 16 meters x 8 meters and has a diagonal measurement of 17.9 meters.