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Using Pythagoras' theorem the diagonal is 16 times the square root of 13 or about 57.689 feet rounded to three decimal places

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How long is diagonal of 30ft x 48ft?

To find the diagonal of a rectangle, you can use the Pythagorean theorem. For a rectangle with dimensions 30 ft and 48 ft, the diagonal (d) can be calculated using the formula (d = \sqrt{(30^2 + 48^2)}). This gives (d = \sqrt{(900 + 2304)} = \sqrt{3204} \approx 56.6) ft. Therefore, the diagonal is approximately 56.6 feet long.


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A rectangle is 4 ft by 6ft What is the length of the diagonal of the rectangle?

To find the length of the diagonal of a rectangle, you can use the Pythagorean theorem. In this case, the diagonal forms the hypotenuse of a right triangle with the sides being the length and width of the rectangle. So, the diagonal (d) can be calculated as d = √(4^2 + 6^2) = √(16 + 36) = √52 ≈ 7.21 feet.


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