The diagonal would be 12.53 meters.
To find the length of the diagonal in a rectangle, use the formula for calculating the hypotenuse of a right triangle: a² = b² + c². a² = 3² + 10² a² = 9 + 100 a² = 109 a = 10.44 m
325 square inches
9
You could draw a rectangle that is 8 units long and one wide.
The area of rectangle is : 1.92
The diagonal is 3.231 meters.
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
15 cm for the diagonal.
To find the length of the diagonal in a rectangle, use the formula for calculating the hypotenuse of a right triangle: a² = b² + c². a² = 3² + 10² a² = 9 + 100 a² = 109 a = 10.44 m
Approximately 15.62 feet.
15 inches (solved with the help of Pythagoras' theorem)
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. The formula is ( d = \sqrt{l^2 + w^2} ), where ( l ) is the length and ( w ) is the width. For a rectangle that is 420 feet long and 75 feet wide, the diagonal is calculated as ( d = \sqrt{420^2 + 75^2} ), which equals approximately 425.6 feet.
"X" = .66
Using Pythagoras' theorem it is 26 inches in length
120 inches (by finding the hypotenuse of a right triangle).
D2 = (57)2 + (24.5)2 = (3,249) + (600.25) = 3,849.25D = sqrt(3,849.25) = 62.0423 (rounded)
D2 = (57)2 + (24.5)2 = (3,249) + (600.25) = 3,849.25D = sqrt(3,849.25) = 62.0423 (rounded)