ok, here we go:
The slope-intercept form is written as y = mx+b, where m is the slope and b is the y-intercept (the point where the line crosses the y-axis). It's usually easy to graph a line using y=mx+b.
With this definition to figure out your equation we know:
m=slope=3
y=5
x=2
plug in all the #'s:
5=3(2)+b
b=-1
your equation is:
y=3x-1
y=2x+13
y = 2x - 1
It is: y = 2x-6
Well. Slope intercept is y= mx + b. With B being the y intercept. If it contains 1,1 and the slope is positive 6, do the equation 1 = 6 (1) + b. 1 = 6 + b -5 = b. So the answer is y = 6x - 5
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Slope: -3 Point: (4, -5) Equation: y = -3x+7
y=2x+1
y=3x-3
y=2x+13
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
The answe iss..... 6
y=2x+1
y = 2x - 1
It is: y = 2x-6
no it is different
y-9 = 3(x-4) y = 3x-3 in slope intercept form