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If you divide length of the opposite side of an angle in a right triangle by the length of the hypotenuse what value do you get?
You get the sine of the angle. For a right triangle: sin (x) = opposite/hypotenuse cos (x) = adj./hypotenuse tan (x) = opposite/adj
What is cos of angle a with a hypotenuse of 13 and adjacent of 5 and a opposite of 12?
Cos(angle) = adjacent / hypotenuse. Cos(a) = a/h Substitute Cos(X) = 5/13 = 0.384615... A = Cos^*-1( 0.384615 .... A = 67.38013505... degrees.
What is the area of a triangle with a hypotenuse of 21 and a leg of 16?
The hypotenuse of 21 does not yield an integral value for the second leg. The legs are 16 and the square root of 185, which is about 13.6 The area of the triangle is 1/2 (16 x 13.6) = about 108.8 212 = 162 + x2 x2 = 185 x = 13.6
The length of sides of right angles of a right angled triangle are 5x and 3x-1 cm if the area of triangle is 60 cm 2 find the hypotenuse?
find the lenght of the hypotenuse of a right triangle whose sides are (3x-1)cm and (x+2)cmImproved answer by David Gambell:-0.5*(3x-1)*5x = 6015x2-5x-120 = 0Solving the quadratic equation gives x a positive value of 3Using Pythagoras: 82+152 = 289 and its square root is 17So the hypotenuse is 17 cm
What is the hypotenuse of a 45-45-90 triangle with an area of 32 sq cm?
Let the base be x and the height be x because their lenghts will be the same as it is a 45-45-90 triangle: 1/2*base*height = area 1/2*x*x = 32 1/2*x2 = 32 Multiply both sides by 2 and then square root both sides: x = 8 cm Use Pythagoras' theorem: 82+82 = 128 and the square root of this is 11.3137085 Therefore: hypotenuse = 11.314 cm correct to 3 decimal places
