The hypotenuse of a triangle 18" x 18" is: 25.46 inches
You get the sine of the angle. For a right triangle: sin (x) = opposite/hypotenuse cos (x) = adj./hypotenuse tan (x) = opposite/adj
The hypotenuse of 21 does not yield an integral value for the second leg. The legs are 16 and the square root of 185, which is about 13.6 The area of the triangle is 1/2 (16 x 13.6) = about 108.8 212 = 162 + x2 x2 = 185 x = 13.6
find the lenght of the hypotenuse of a right triangle whose sides are (3x-1)cm and (x+2)cmImproved answer by David Gambell:-0.5*(3x-1)*5x = 6015x2-5x-120 = 0Solving the quadratic equation gives x a positive value of 3Using Pythagoras: 82+152 = 289 and its square root is 17So the hypotenuse is 17 cm
Let the base be x and the height be x because their lenghts will be the same as it is a 45-45-90 triangle: 1/2*base*height = area 1/2*x*x = 32 1/2*x2 = 32 Multiply both sides by 2 and then square root both sides: x = 8 cm Use Pythagoras' theorem: 82+82 = 128 and the square root of this is 11.3137085 Therefore: hypotenuse = 11.314 cm correct to 3 decimal places
No. It has to lie in between -1 an +1 inclusive. Cos x = adjecent/hypotenuse and for cos x to be greater than 1, you need the adjacent to be bigger than the hypotenuse. The hypotenuse is always the biggest side.
Use Pythagoras' theorem: 12+12 = 2 and the square root of this is hypotenuse which is about 1.414213562 meters
(1/2) x (length of the hypotenuse) x sqrt(3)
The six main trigonometric functions are sin(x)=opposite/hypotenuse cos(x)=adjacent/hypotenuse tan(x)=opposite/adjacent csc(x)=hypotenuse/opposite cot(x)=adjacent/opposite sec(x)=hypotenuse/adjacent Where hypotenuse, opposite, and adjacent correspond to the three sides of a right triangle and x corresponds to an angle in that right triangle.
By using the sine ratio, you know two sides of the right triangle (the opposite and hypotenuse) and so can work out the third side (adjacent) using Pythagoras (opposite2 + adjacent2 = hypotenuse2). You can then use the trigonometric ratios to calculate cos θ, sec θ, cot θ, and the hypotenuse you already have. Sin θ = opposite/hypotenuse = 2/x ⇒ opposite = 2, hypotenuse = x, and adjacent = √(x2 - 4) Thus: cos θ = adjacent/hypotenuse = √(x2 - 4)/x sec θ = 1/cos θ = hypotenuse/adjacent = x/√(x2 - 4) cot θ = 1/tan θ = adjacent/opposite = √(x2 - 4)/2 Hypotenuse = x.
The hypotenuse of a triangle 18" x 18" is: 25.46 inches
You get the sine of the angle. For a right triangle: sin (x) = opposite/hypotenuse cos (x) = adj./hypotenuse tan (x) = opposite/adj
-- The length of each leg is (length of the hypotenuse) / sqrt(2) = 0.7071 x (hypotenuse). -- The length of the hypotenuse is (length of either leg) x sqrt(2) = 1.414 x (leg)
The answer is 5 degrees.
Cos(x) = 1 - x2/2! + x4/4! - x6/6! + ... where x is measured in radians
You mean a isoceles? An isoceles wouldn't have a right angle but would have 2 equal sides and 1 unequal in which case the values are x and x(root)2, In a right triangle the values are x , 2x , and x(root)3. The short side is x, and the long leg is 2x and the hypotenuse is x(root)3. If you are looking for the hypotenuse equation it is a(squared) + b(squared) = c(squared) in other words, leg one squared plus leg two squared equals hypotenuse squared.
They are described by the famous Pythagoras theorem, if "a" and "b" are the legs and "h" the hypotenuse, then h x h = (a x a) + (b x b) Also a = h x sinB (where B is the internal angle (of the triangle) between the hypotenuse and side b and b = h x sinA (where A is the internal angle (of the triangle) between the hypotenuse and side a