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What is the perpendicular distance from the point 2 4 to the line y equals 2x plus 10?
Wiki User
∙ 6y ago
Known equation: y = 2x+10
Perpendicular equation through point (2, 4): 2y = -x+10
Both equations intersect at: (-2, 6)
Perpendicular distance from (2, 4) to (-2, 6) is 2 Times Square root of 5 by using the distance formula
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoIt is sqrt(20)= 2*sqrt(5).
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What is the perpendicular distance from the point 2 4 to the line y equals 2x plus 10 on the Cartesian plane?
Known equation: y = 2x+10 Perpendicular equation: 2y = -x+10 Both equations intersect at: (-2, 6) Distance from (2, 4) to (-2, 6) is sq rt of 20 using the distance formula
What is foot of perpendicular?
The foot of a perpendicular is the lowest part of the perpendicular [Kinda like the feet of people]||||_____^ This is the point where the foot of the perpendicular meets the line.
When you construct a parallel to a line through a point not on the line using paper folding what construction can you perform twice?
You construct a line perpendicular to the original and then a line perpendicular to this second line.
What is the perpendicular distance from the point 2 4 to the straight line y equals 2x plus 10?
It is 2√5 ≈ 4.47 units.To solve this:Find the equation of the line perpendicular to y = 2x + 10 that passes through the point (2, 4);Find the point where this line meets y = 2x + 10Find the distance from this point to (2, 4) using PythagorasThe slope of the perpendicular line (m') to a line with slope m is such that mm' = -1, ie m' = -1/mFor y = 2x + 10, the perpendicular line has slope -1/2, and so the line that passes through (2, 4) with this slope is given by:y - 4 = -½(x - 2)→ 2y - 8 = -x + 2→ 2y + x = 10To find where this meets the line y = 2x + 10, substitute for y in the equation of the perpendicular line and solve for x:y = 2x + 102y + x = 10→ 2(2x + 10) + x = 10→ 4x + 20 + x = 10→ 5x = -10→ x = -2Now use one of the equations to solve for y:y = 2x + 10→ y = 2(-2) + 10→ y = -4 + 10 = 6This the perpendicular line from (2, 4) meets the line y = 2x + 10 at the point (-2, 6)The distance between these two points is given by:distance = √((-2 - 2)² + (6 - 4)²) = √(16 + 4) = √20 = 2√5 ≈ 4.47 units
What is the slope of a line which is perpendicular to the line that has an equation of y equals x plus 13?
negative 1
What is the definition of distance from point to line?
It the point is on the line the distance is 0. If the point is not on the line, then it is possible to draw a unique line from the point to the line which is perpendicular to the line. The distance from the point to the line is the distance along this perpendicular to the line.
What is the perpendicular distance from the point 4 -2 to the straight line of 2x -y -5 equals 0?
Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5
Which of these is equal to the distance from a point to a line?
the length of a perpendicular segment from the point to the line
The shortest distance form a point to a straight line is?
Its perpendicular distance.
What is the perpendicular ditance from the point 7 5 to the line 3x plus 4y -16 equals 0?
If you mean the perpendicular distance from the coordinate of (7, 5) to the straight line 3x+4y-16 = 0 then it works out as 5 units.
What is the shortest distance between a point and a line?
The length of a line segment that starts at the point and is perpendicular to the original line.
Is the shortest point of a distance measured along the perpendicular segments from the point to the line?
No it is measured from the edge
What is the perpendicular distance from the point of 2 4 to the straight line of y equals 2x plus 10 on the Cartesian plane?
The perpendicular distance from (2, 4) to the equation works out as the square root of 20 or 2 times the square root of 5
When a point is reflected over a horizontal line and is not on the line. Does the y-coordinate stays the same?
No. It changes by double the (perpendicular) distance from the point to the line.
What is the perpendicular distance from the point of 7 5 to the straight line whose equation is 3x plus 4y minus 16 equals 0?
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point of intersection: (4, 1) Distance: (7-4)2+(5-1)2 = 25 and the square root of this is the perpendicular distance which is 5 units of measurement
What is the perpendicular distance from the point 4 -2 to the line 2x -y -5 equals 0?
From the given information the perpendicular line will form an equation of 2y = -x and both simultaneous line equations will intersect each other at (2,-1) and so distance from (4, -2) to (2, -1) is the square root of 5 by using the distance formula.
The distance from a point C to the line AB is the length of the segment from C to AB?
perpendicular
