y - 7 = -13(x - 5)
apexvs
The point slope equation is (y - 9) = 5*(x - 4)
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
There are infinitely many lines that pass through the point (5, 5). The point slope equation for a straight line with a given slope m through a point (x0, y0) is given by: y - y0 = m(x - x0) Which means that the straight line through the point (5, 5) will have an equation of the form: y - 5 = m(x - 5) where m is the slope of the line - you'll need to replace that with the slope you require.
Another point is needed to work out the slope and its straight line equation. Slope is worked out as: (y2-y1)/(x2-x1) ----------------------- With slope m and going through a point (x0, y0), a line has equation: y - y0 = m(x - x0) Thus the point-slope equation of a line with slope m through the point (-1, 2) is given by: y - 2 = m(x - -1) → y - 2 = m(x + 1)
The equation is x = -7.
That will depend on the value of the slope which has not been given.
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
If you mean: slope of -13 and point of (5, 7) then the equation is y = -13x+72
write an equation that has a slope 7 and passes through the point (2,17)
Point: (1, 4) Slope: -3 Equation: y = -3x+7
The point slope equation is (y - 9) = 5*(x - 4)
You can have infinitely many lines through one specific point, each with a different equation. If you want to have a general equation for ANY line that goes through that point, use the point-slope equation for a line, and use a variable for the slope.
It is: y = -10x+14
It is: y = -10x+14
Slope: -13 Point: (5, 7) Equation: y = -13x+72 whereas -13 is the slope and 72 is the y intercept