It is sqrt(41) = 6.4031 inches, approx.
The radius of the circle that is perpendicular to a chord intersects the chord at its midpoint, so it is said to bisect the chord.
If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.
The relationship between the chord and the radius of the circle is Length of the chord = 2r sin(c/2) where r = radius of the circle and c = angle subtended at the center by the chord
False
Radius
Half of the chord, the distance of the midpoint from the center, and a radius, form a right triangle, with the radius as its hypotenuse. (4.5)2 + (6)2 = (radius)2 (20.25) + (36) = 56.25 = R2 Radius = 7.5 inches
The radius of the circle that is perpendicular to a chord intersects the chord at its midpoint, so it is said to bisect the chord.
If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.
Then the radius bisects the chord.
No, but the diameter of a circle is its largest chord
A chord is when two points in a circle are connected by segment. A diameter is a chord, but not a radius. The radius is not a complete segment in the circle
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The relationship between the chord and the radius of the circle is Length of the chord = 2r sin(c/2) where r = radius of the circle and c = angle subtended at the center by the chord
a chord is a line between two points on the circle the radius is a line from the center to the circle
Bisects
Perpendicular.
No, a radius connects the center of a circle the a point on the outside, a chord connects to points on the outside of the circle. Thanks for asking on