-1
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],and that's the equation.
Inscribed angle
True
it lies in the 2nd and 4th quadrants
Points: (-3, 2) and (7, 6) Slope: 2/5 Equation: 5y-2x = 16 x intercept: (-8, 0)
Without an equality sign it can not be considered to be an equation
To determine which set of points lies within plane ( l ), you need to check if the coordinates of each point satisfy the plane's equation. A point ((x, y, z)) lies in the plane if it fulfills the equation of the plane, typically expressed in the form ( Ax + By + Cz + D = 0 ). By substituting the coordinates of the points into this equation, you can identify which points lie within the plane. Points that make the equation true are considered to be on or within the plane.
Since there are no "following" points, none of them.
There are infinitely many points. One of these is (10, 0).
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],and that's the equation.
To prove that three points are colinear, pick two points and form the equation of the line they describe, and then see if the third point lies on that line.
The points that lie on a circle centered at the origin (0, 0) with a radius of 10 satisfy the equation (x^2 + y^2 = 10^2) or (x^2 + y^2 = 100). This means any point ((x, y)) that meets this equation, such as (10, 0), (0, 10), (-10, 0), and (0, -10), as well as any other points that fall on the circle's perimeter, will lie on the circle. In general, points can be expressed in parametric form as ((10 \cos \theta, 10 \sin \theta)) for any angle (\theta).
Done see any following points. Ill give you a few that come from the equation. x=1 and y=5 x=2 and y=6 x=3 and y=9 x=11 and y=105
If you mean as on the Cartesian plane then the following key notes are applicable:-Diameter: 14 inchesRadius: 7 inchesCentre of the circle is at: (7, 7)Equation of the circle: (x-7)^2 +(y-7)^2 = 49
The first graph consists of all points whose coordinates satisfy the first equation.The second graph consists of all points whose coordinates satisfy the second equation.The point of intersection lies on both lines so the coordinates of that poin must satisfy both equations.
To determine which point lies on the line described by the equation ( y + 4 = 4x - 3 ), we first simplify the equation to ( y = 4x - 7 ). Then, we can test specific points by substituting their coordinates into this equation to see if they satisfy it. For instance, if we test the point (2, 1), substituting ( x = 2 ) gives ( y = 4(2) - 7 = 1 ), confirming that (2, 1) lies on the line.
To determine which pair of points lies on the equation (3x - y = 2), substitute the coordinates of each point into the equation. For a point ((x, y)) to lie on the line, it must satisfy the equation when the values of (x) and (y) are plugged in. For example, the point ((1, 1)) does not satisfy the equation, but the point ((2, 4)) does, as substituting (x = 2) gives (3(2) - 4 = 2). Thus, you need to check the specific points provided to identify those that satisfy the equation.