-1
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],and that's the equation.
Inscribed angle
True
it lies in the 2nd and 4th quadrants
Points: (-3, 2) and (7, 6) Slope: 2/5 Equation: 5y-2x = 16 x intercept: (-8, 0)
Without an equality sign it can not be considered to be an equation
Since there are no "following" points, none of them.
There are infinitely many points. One of these is (10, 0).
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],and that's the equation.
To prove that three points are colinear, pick two points and form the equation of the line they describe, and then see if the third point lies on that line.
Done see any following points. Ill give you a few that come from the equation. x=1 and y=5 x=2 and y=6 x=3 and y=9 x=11 and y=105
If you mean as on the Cartesian plane then the following key notes are applicable:-Diameter: 14 inchesRadius: 7 inchesCentre of the circle is at: (7, 7)Equation of the circle: (x-7)^2 +(y-7)^2 = 49
The first graph consists of all points whose coordinates satisfy the first equation.The second graph consists of all points whose coordinates satisfy the second equation.The point of intersection lies on both lines so the coordinates of that poin must satisfy both equations.
an equation
I think you mean Gaza
Netherlands
It is every point in the plane that lies on the straight line defined by the equation -5x + 4y = -3. Since there are an infinite number of points on that line, there is no point in trying to list them.