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The number of diagonals in a polygon with n sides is given by n(n-3)/2 (see related question). So, 35 = n(n-3)/2 is what we have to solve. 70 = n(n-3) 70 = n2 - 3n n2 - 3n - 70 = 0 Factorizing the quadratic: (n-10)(n+7) = 0 This gives solutions n = 10 and n = -7. Clearly only the positive answer makes any sense (a shape cannot have minus seven sides!) so our shape has 10 sides: it is a decagon.
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How many diagonals in decagon?
There are 35 diagonals in a 10 sided decagon
How many diagonals in decagon have?
35
How many diagonals are in a 35 side polygon?
There are 560 diagonals by using the diagonal formula
Does a nonagon have 35 or 27 diagonals?
It has 27.
How many diagonals can you drawn from one vertex in a 35 sided polygon?
A diagonal of a polygon is a segment drawn from one vertex to another non-adjacent vertex in a polygon. This leaves 32 diagonals that can be drawn from one vertex in a 35 sided polygon.
How many diagonals does 35-gon?
It has 0.5*(35^2 -3*35) = 560 diagonals
How many diagonals in decagon?
There are 35 diagonals in a 10 sided decagon
If a polygon has 35 diagonals then how many sides does it have?
(35*(35-3))/2 (35*32)/2 1120/2 560 diagonals
How many diagonals are in a10 sided polygon?
It has 35 diagonals
How many diagonals does a 10 sided shape have?
35 diagonals
How many diagonals are there in a 35-sided polygon?
The number of diagonals is n(n-1)/2 - n substitute n=35 35(34)/2 - 35 = 560
What shape has 35 diagonals?
octagon
How many diagonals are in a Decagon?
35.
How many diagonals in decagon have?
35
how many diagonals decagon have?
35
How many sides does a polygon have with 35 diagonals?
It has 10 sides because using the formula 0.5*(102-30) = 35 diagonals
How many diagonals are in a 35 side polygon?
There are 560 diagonals by using the diagonal formula
