They touch each other at (0, 100) on the x and y axis.
20
x = -1.75
54(x)+52+32(y)+72=212
subtraction; 80-y= 52. 28+52 =80
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
... You have to know what x and y are first.
They touch each other at (0, 100) on the x and y axis.
If: 20x+5y = 15 Then: y = -4x+3
20
20x + 80y = 0Subtract 20x from each side of the equation:80y = -20xDivide each side by 80:y = -1/4 xm = -1/4b = 0
The graphs of the two equations will intersect when x² + 20x + 100 = y = x² - 20x + 100 Subtracting x² +100 from both sides you get 20x = -20x that will only be true when x = 0. At x = 0, y = 100 for both equations - so the point of contact would be (0,100)
x = -1.75
If: 20x+80y = 0 Then: 80y = -20x And: y = -0.25x So the slope is -0.25 and it has no y intercept
If: y = 10x -12 and y = x^2 +20x +12 Then: x^2 +20x +12 = 10x -12 Transposing terms: x^2 +10x +24 = 0 Factorizing: (x+6)(x+4) = 0 => x = -6 or x = -4 Points of intersection by substitution are at: (-6, -72) and (-4, -52)
54(x)+52+32(y)+72=212
If the equation is -20x-5y=40 then the answer is -5y=20x+40 which equals y=-4x-8 If the equation is -20x+5y=40 then the answer is 5y=20x+40 which equals y=4x+8