If: y = 10x -12 and y = x^2 +20x +12 Then: x^2 +20x +12 = 10x -12 Transposing terms: x^2 +10x +24 = 0 Factorizing: (x+6)(x+4) = 0 => x = -6 or x = -4 Points of intersection by substitution are at: (-6, -72) and (-4, -52)
I x=5 and y=2, then (5x5)=25 plus (9x2)=18. 25+18=43
3y+5=y-25 2y=-30 y= -15
2x + y = 25 x + y = 14 Subtract second equation from the first: x = 11 Substitute this value of x in the second equation: 11 + y = 14 ie y = 3
When x = -5
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
They touch each other at (0, 100) on the x and y axis.
If: 20x+5y = 15 Then: y = -4x+3
20
20x + 80y = 0Subtract 20x from each side of the equation:80y = -20xDivide each side by 80:y = -1/4 xm = -1/4b = 0
The graphs of the two equations will intersect when x² + 20x + 100 = y = x² - 20x + 100 Subtracting x² +100 from both sides you get 20x = -20x that will only be true when x = 0. At x = 0, y = 100 for both equations - so the point of contact would be (0,100)
x = -1.75
If: 20x+80y = 0 Then: 80y = -20x And: y = -0.25x So the slope is -0.25 and it has no y intercept
If the equation is -20x-5y=40 then the answer is -5y=20x+40 which equals y=-4x-8 If the equation is -20x+5y=40 then the answer is 5y=20x+40 which equals y=4x+8
Well you can find what it equals in terms of x. If you know that y plus y equals 25 to the power of 25 then you know that 2y=25^25 which means that y=(25^25)/2 - this is a huge number. To find x+y you just add x to what y equals so you get x+(25^25)/2
y= -25
y + x = 9 10y + 20x = 100 This is a basic linear system of equalities. We can start by rewriting the first equation as: -10y - 10x = -90 by multiplying the equation by -10, from here we can eliminate y and solve for x (-10y - 10x = -90) + (10y + 20x = 100) = (10x = 10) This yields x = 1, and by plugging x into the first equation y = 8