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A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
Each of them is 14.14 inches long. (rounded)
8.9
The diagonal is about 16.97 inches long.
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
107.8 inches
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
Using Pythagoras' theorem it is 26 inches in length
Each of them is 14.14 inches long. (rounded)
8.9
The diagonal is about 16.97 inches long.
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
26.4 inches for the diagonal.
15 inches (solved with the help of Pythagoras' theorem)
The diagonal is 221.2 inches long.
Do the math.96 x 3 = 288the table is 288 inches long.
You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring! Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com