Yorokobifai
Height = H0 + V0 T +1/2a T2
H0 = height when released = +5
V0 = velocity when released = 20 up = +20
a = acceleration of gravity = 32.2 down = -32.2
When the ball hits the ground, "Height" = 0
5 + 20 T - 16.1 T2 = 0
Easier . . . 16.1 T2 - 20 T - 5 = 0
Quadratic formula: T = 1/32.2 [ 20 +/- sqrt(400 + 322) ]
T = (20 +/- 26.87) / 32.2
T = -0.213 seconds
T = 1.456 seconds (rounded)
Wiki User
∙ 13y agoFinal Velocity- Initial Velocity Time
You can't. You need either the final velocity or the acceleration of the object as well, and then you can substitute the known values into a kinematics equation to get the initial velocity.
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
Acceleration = Final velocity - Initial velocity / time
The initial velocity is zero. In most basic physics problems like this one the initial velocity will be zero as a rule of thumb: the initial velocity is always zero, unless otherwise stated, or this is what you are solving for Cases where the initial velocity is not zero examples a cannon ball is shot out of a cannon at 50 mph a ball is thrown from at a speed of 15 mph etc
The equation for finding the acceleration of an object moving in a straight line is a = (v_f - v_i) / t, where a is acceleration, v_f is the final velocity, v_i is the initial velocity, and t is the time taken.
Final Velocity- Initial Velocity Time
The equation that relates the distance traveled by a constantly accelerating object to its initial velocity, final velocity, and time is the equation of motion: [ \text{distance} = \frac{1}{2} \times (\text{initial velocity} + \text{final velocity}) \times \text{time} ] This equation assumes constant acceleration.
Acceleration is calculated using the equation a = (v_f - v_i) / t, where a is the acceleration, v_f is the final velocity, v_i is the initial velocity, and t is the time taken to change from the initial velocity to the final velocity.
The slope of a distance-velocity squared graph is constant because the velocity squared term stays constant, resulting in a straight line. In contrast, a distance-velocity graph is not constant because the velocity term changes over time, leading to a non-linear relationship between distance and velocity.
The equation for acceleration is given by the formula: acceleration = (final velocity - initial velocity) / time. This equation calculates the rate at which an object's velocity changes over time.
The equation that relates acceleration (a), initial velocity (u), final velocity (v), and time (t) for an object under constant acceleration is: v = u + at.
The equation for finding acceleration of an object moving in a straight line is: acceleration (a) = change in velocity (Δv) / time taken (Δt). Mathematically, it can also be written as a = (v_f - v_i) / t, where v_f is the final velocity, v_i is the initial velocity, and t is the time taken.
You can use the equation: Displacement = (final velocity squared - initial velocity squared) / (2 * acceleration). Plug in the values of final velocity, initial velocity, and acceleration to calculate the displacement.
To find the final velocity of an object, you can use the kinematic equation: final velocity = initial velocity + (acceleration * time). If acceleration is constant, you can also use the equation: final velocity = initial velocity + (2 * acceleration * distance). The initial velocity can be found by measuring the velocity of the object at the beginning of its motion using a speedometer or other measuring device.
This equation represents the final velocity squared when an object is accelerating from an initial velocity over a certain distance. It is derived from the kinematic equation (v^2 = u^2 + 2as), where (v) is the final velocity, (u) is the initial velocity, (a) is the acceleration, and (s) is the distance traveled.
v1 = initial velocity v2 = final velocity