0
Height = H0 + V0 T +1/2a T2
H0 = height when released = +5
V0 = velocity when released = 20 up = +20
a = acceleration of gravity = 32.2 down = -32.2
When the ball hits the ground, "Height" = 0
5 + 20 T - 16.1 T2 = 0
Easier . . . 16.1 T2 - 20 T - 5 = 0
Quadratic formula: T = 1/32.2 [ 20 +/- sqrt(400 + 322) ]
T = (20 +/- 26.87) / 32.2
T = -0.213 seconds
T = 1.456 seconds (rounded)
What else can I help you with?
What is the equation for acceleration?
Final Velocity- Initial Velocity Time
How do you find the initial velocity given only the distance and the time traveled?
You can't. You need either the final velocity or the acceleration of the object as well, and then you can substitute the known values into a kinematics equation to get the initial velocity.
How to find the height of the projectile launch if the angle velocity and the distance are given?
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
What formula do you use to calculate the acceleration of an object moving in a straight line?
Acceleration = Final velocity - Initial velocity / time
If a small marble is dropped straight downward what is the initial velocity of the marble?
The initial velocity is zero. In most basic physics problems like this one the initial velocity will be zero as a rule of thumb: the initial velocity is always zero, unless otherwise stated, or this is what you are solving for Cases where the initial velocity is not zero examples a cannon ball is shot out of a cannon at 50 mph a ball is thrown from at a speed of 15 mph etc
What is the equation for finding the alliteration of an object moving in a straight line?
The equation for finding the acceleration of an object moving in a straight line is a = (v_f - v_i) / t, where a is acceleration, v_f is the final velocity, v_i is the initial velocity, and t is the time taken.
What is the equation for acceleration?
Final Velocity- Initial Velocity Time
If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?
The equation that relates the distance traveled by a constantly accelerating object to its initial velocity, final velocity, and time is the equation of motion: [ \text{distance} = \frac{1}{2} \times (\text{initial velocity} + \text{final velocity}) \times \text{time} ] This equation assumes constant acceleration.
What is the linear acceleration equation and how is it used to calculate the acceleration of an object moving in a straight line?
The linear acceleration equation is a (vf - vi) / t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time. This equation is used to calculate the acceleration of an object moving in a straight line by finding the change in velocity over time.
How to find the initial velocity of an object in motion?
To find the initial velocity of an object in motion, you can use the equation: initial velocity final velocity - (acceleration x time). This equation helps you calculate the starting speed of the object based on its final velocity, acceleration, and the time it took to reach that final velocity.
What equation do you use to calculate acceleration?
Acceleration is calculated using the equation a = (v_f - v_i) / t, where a is the acceleration, v_f is the final velocity, v_i is the initial velocity, and t is the time taken to change from the initial velocity to the final velocity.
What equation do you use for acceleration?
The equation for acceleration is given by the formula: acceleration = (final velocity - initial velocity) / time. This equation calculates the rate at which an object's velocity changes over time.
If an object is accelerating what equation relates the acceleration of that object the initial velocity and the final velocity and time?
Vf = Vi + at Where Vf = final velocity Vi = initial velocity a = acceleration t = time
Why is the slope of a distance velocity squared graph straight and a distance velocity graph is not?
When acceleration is constant, one equation of kinematics is: (final velocity)^2 = 2(acceleration)(displacement) + (initial velocity)^2. When you are graphing this equation with displacement or position of the x-axis and (final velocity)^2 on the y-axis, the equation becomes: y = 2(acceleration)x + (initial velocity)^2. Since acceleration is constant, and there is only one initial velocity (so initial velocity is also constant), the equation becomes: y = constant*x + constant. This looks strangely like the equation of a line: y = mx + b. Therefore, the slope of a velocity squared - distance graph is constant, or there is a straight line. Now, when you graph a velocity - distance graph, the y axis is only velocity, not velocity squared. So if: v^2 = mx + b. Then: v = sqrt(mx + b). Or: y = sqrt(mx + b). This equation is not a straight line. For example, pretend m = 1 and b = 0. So the equation simplifies to: y = sqrt(x). Now, make a table of values and graph: x | y 1 | 1 4 | 2 9 | 3 etc. When you plot these points, the result is clearly NOT a straight line. Hope this helps!
What is the equation for finding the aceleration of an object moving in a straight line?
The equation for finding acceleration of an object moving in a straight line is: acceleration (a) = change in velocity (Δv) / time taken (Δt). Mathematically, it can also be written as a = (v_f - v_i) / t, where v_f is the final velocity, v_i is the initial velocity, and t is the time taken.
How do you find displacement when you only have acceleration initial velocity and final velocity?
You can use the equation: Displacement = (final velocity squared - initial velocity squared) / (2 * acceleration). Plug in the values of final velocity, initial velocity, and acceleration to calculate the displacement.
How do you find final and initial velocity?
You use the information you're given, along with the equations and formulas you know that express some kind of relationship between the information you're given and the initial and final velocity.
