Q: A man walks 30 meters forward then turns around and walks backward 10 meters what is the displacement of the man?

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20 meters.

If you have moved forward and backward, hence ending up at the same point you started, then displacement is zero. That's because Displacement takes into account the direction - hence a vector quantity.The distance only bothers about the distance - hence it doesn't matter if you came to where you started. So in total, 5 meters up and 5 down is 10. Distance = 10

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80

20m

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20 meters.

The distance traveled would be 135 meters (100m forward + 35m backward). The displacement would be 65 meters forward (100m - 35m) as it measures the shortest distance from the initial point to the final point.

If you have moved forward and backward, hence ending up at the same point you started, then displacement is zero. That's because Displacement takes into account the direction - hence a vector quantity.The distance only bothers about the distance - hence it doesn't matter if you came to where you started. So in total, 5 meters up and 5 down is 10. Distance = 10

The distance traveled is 135 meters (100 m forward + 35 m backwards). However, the displacement is 65 meters forward (100 m - 35 m) since displacement is the shortest distance from the initial to the final position in a straight line.

it is around about 12 meters forward 5 meters right and then 15 meters forward

If you come back to the starting point your displacement is zero

zero

Displacement is the shortest distance travelled . formula of Displacement= speed * time in meters

Mary's walk resulted in a displacement of 500 meters east.

The combined displacement vector would be 8 meters in the same direction as the individual vectors, as you simply add the magnitudes of the vectors together.

To determine the distance the book has been moved, we can use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy. Given that the work done is 2.7J and the force applied is 4.5N, we can calculate the distance using the formula for work: work = force x distance. Rearranging the formula to solve for distance, we get distance = work / force. Plugging in the values, distance = 2.7J / 4.5N = 0.6 meters. Therefore, you have moved the book 0.6 meters across the table.

If the train is going at a constant speed, it will make no difference whether she runs forward or backward. There will only be a difference if it is accelerating or slowing down. If it is accelerating you tend to be thrown backward, so it is easier to run back than forward. If it is braking you are thrown forward so it is easier to run forward than backward. The force on the body is the product of the acceleration or retardation and the mass of the body: F (Newtons) = mass (kg) x acceleration (meters/sec2)