(81/4)*(sqrt(3))
The area of a triangle is expressed by 1/2 bh, where b is the base length of the triangle, and h is the vertical height. In this instance, the base is equal to 9. The height of an equilateral triangle can be found using the Pythagorean theory with a being half the length of one side of the equilateral triangle, h being the height, and c (the hypotenuse) being the length of one side of the equilateral triangle.
Thus,
a2+h2=c2
(9/2)2+h2=(9)2
h2=81-(81/4)
h=9(sqrt(3))/2
So, A=1/2 bh=1/2 (9)(9(sqrt(3))/2)=(81/4)*(sqrt(3))
Area = 1/2 * length * height
height is square root 2(9)2 = square root 2(81)=square root 192 = 13.85640646...
1/2 * 13.85640646 * 9 = 62.3538290 est. to 62.3 square inch
15.588 square inches.
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
Area of a triangle = 1/2*base*height Use Pythagoras to find the height which is 7.794228634 inches Area = 1/2*9*7.794228634 = 35.07402885 square inches Answer: 35 square inches to the nearest square inch.
A triangle with side a: 6, side b: 6, and side c: 6 inches has an area of 15.59 square inches.
62.354 inches2
15.588 square inches.
Its area is 46.8 (46.76533) square inches.
21.20
Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.
Area of equilateral triangle: 0.5*7*7*sin(60 degrees) = 21.2 square inches
27.713 square inches.
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 Times Square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
By definition, an equilateral triangle has all three sides of equal length! So it is impossible for it to have sides of length 10 inches and 7 inches!
Area of equilateral triangle: 0.5*8*8*sin(60 degrees) = 27.7 square inches rounded
Area of a triangle = 1/2*base*height Use Pythagoras to find the height which is 7.794228634 inches Area = 1/2*9*7.794228634 = 35.07402885 square inches Answer: 35 square inches to the nearest square inch.
I'm showing it with absolute proof. Equilateral triangle both side are same in size & same angel.It's given with the sides of 10 inches & height 7 inches. I don't need to count the height(7),just use side(10).The formula is=Area of a equilateral triangle="root over of 3" /4 * "a square"Now I use this formula,where "a" is 10. So the answers come=43.3,which is 44.So the Correct answer is=44 inches.* * * * *Mostly correct, but:43.3 should be rounded to 43, not 44.The units for the area should be square inches, not inches.