a2 + 28a + 27
As it stands, there's no answer, because there's no question here.
The expression can be factored: (a+1) x (a+27) , but that's just a different way to write
the same expression, and there's still no question.
If we were told that some number is equal to this expression, then we could calculate
the value of 'a' that makes that a true statement.
For example, if this expression is 'zero', then ( a = -1 ) and ( a = -27 ) are both true.
But so far, there's no question asked, so there's no answer.
a2 + 12a + 27 = (a + 3)(a + 9)
(a + 9)(a - 3)
a2 - 4a + 4
5 - a - 1 + c - 6a2 + a2
5a+3a2a2= 8a a2
a2 + 28a + 27 = 0 (a + 1)(a + 27) = 0 a = -1 or -27 However, the second line is the factorised form, the third is what a is equal to
a2 + 12a + 27 = (a + 3)(a + 9)
(a + 9)(a - 3)
( a2 ) ( a2+1 )
(a2 + a + a2) = (2a2 + a) = a (2a + 1)
a2 - 4a + 4
a2 + -5a2 - a2 - a = a2 - 5a2 - a2 - a = a2 - 6a2 - a = -5a2 - a
a2 + a2 = 2a2
a2+9a+20 = (a+4)(a+5) when factored
a2+2a2b+2ab2+b2
5 - a - 1 + c - 6a2 + a2
A42a